Answer:
Correct answers are: 4 and 6
Explanation:
First of all this law is very important and almost every where this law is used in current and according to this law,
1. All incoming current to a particular junction is equal to all out going current from that junction .
2. Sum of all the voltage drop across all the element in the particular loop is zero
Current: it is rate of change of charge per unit time and denoted by I.
V=IR
Hence correct options are: 4 and 6
It would be balanced. (No acceleration - No change in motion)
Answer:
5.1 rad/s
Explanation:
Mechanical energy of the system is conserved since no external work is done on the sphere.
![mgh = mv^2/2 + I\omega^2/2](https://tex.z-dn.net/?f=mgh%20%3D%20mv%5E2%2F2%20%2B%20I%5Comega%5E2%2F2)
Substituting v = ωr and I = 2 m r^2/5, we get,
=> ![mgh=m(\omega r)^2/2 + (2\omega r^2/5)\omega^2/2](https://tex.z-dn.net/?f=mgh%3Dm%28%5Comega%20r%29%5E2%2F2%20%2B%20%282%5Comega%20r%5E2%2F5%29%5Comega%5E2%2F2)
=> ![mgh = m\omega^2r^2/2 + m\omega^2r^2/5](https://tex.z-dn.net/?f=mgh%20%3D%20m%5Comega%5E2r%5E2%2F2%20%2B%20m%5Comega%5E2r%5E2%2F5)
=> ![gh =\omega^2r^2/2+\omega^2r^2/5](https://tex.z-dn.net/?f=gh%20%3D%5Comega%5E2r%5E2%2F2%2B%5Comega%5E2r%5E2%2F5)
=> ![gh = 7\omega^2 r^2/10](https://tex.z-dn.net/?f=gh%20%3D%207%5Comega%5E2%20r%5E2%2F10)
=> ![\omega r = (10gh/7)^{1/2}](https://tex.z-dn.net/?f=%5Comega%20r%20%3D%20%2810gh%2F7%29%5E%7B1%2F2%7D)
=>
= 5.1 rad/s
Answer:
3.5mm I guess
Explanation:
More professional people will give you the correct answer... this is just a try
Answer:
Explanation:
Let the amplitude of individual wave be I and resultant amplitude be 1.703 I . Let the phase difference be Ф in terms of degree
From the formula of resultant vector
(1.703I)² = I² + I² + 2 I² cosФ
2.9 I² = 2I² + 2 I² cosФ
.9I² = 2 I² cosФ
cosФ = .9 / 2
= .45
Ф = 63.25 .