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3 years ago

Can genes make a different skin colored child

Chemistry

1 answer:

vitfil [10]3 years ago

7 0

Answer:

Scientists have figured out that several genes are involved in skin color.

Explanation:

Parents can have children with skin color that is significantly lighter or darker than their own. Sometimes a particular gene can have a much bigger effect than other genes.

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A neutral atom has 1 valence electron and its atomic mass is 39. How many

uranmaximum [27]

Answer: I think probaly wrong so probaly dont

listen to me

Explanation:

5 0

3 years ago

Which of the following would qualify as matter?

Olin [163]

Answer:

the water, gasoline, sand, and sugar

Explanation:

6 0

3 years ago

Read 2 more answers

Please somebody give me the answers

RSB [31]

Answer:

1. 9.4 grams of methane produce 25.85 grams of CO2

2.Grams of water produced = 11.81 grams

3.Mass of Methane produced by 10.1 gram of O2 = 2.52 grams

4.Amount of methane consumed = 46.9 grams

5. Grams of Co2 produced = 8.32 grams

Explanation:

Molar masses :

Methane = CH4 = mass of C + 4x (mass of H)

CH4 = 12 +4(1) = 16 grams

1 mole of CH4 = 16 gram

Oxygen O2 = 2 x (mass of O) = 2x(16) = 32 gram (1 mole of O2 =32 gram)

Carbon Dioxide =CO2 = mass of C + 2(mass of O)

= 12 + 2(16)

= 44 grams (1 mole of CO2 = 44 gram )

Water = H2O = 18 grams ( 1 mole of H2O = 18 gram)

1 mole of each molecule is equal to their molar masses

The balanced equation is :

$1CH_{4}(g)+2O_{2}\rightarrow 1CO_{2}+2H_{2}O(l)$

According to Stoichiometry :

1 mole of CH4 = 2 Mole of O2 = 1 mole of CO2 = 2 mole of H2O

1. From the equation ,

1 mole of methane produce =1 mole of CO2

16 gram of methane = 44 gram of CO2

1 gram of methane =

$\frac{44}{16}$ gram of CO2

9.4 gram of CH4 =

$\frac{44}{16}\times 9.4$ gram of CO2

= 25 .85 gram of CO2

2 mole of O2 produces = 2 mole of H2O(water)

1 mole of O2 produces = 1 mole of H2O

32 gram of O2 = 18 gram of water

1 gram of O2 =

$\frac{18}{32}$

21 gram of O2 =

$\frac{18}{32}\times 21$

11.81 gram of water

3. 1 mole of CH4 = 2 mole of O2

16 gram of CH4 = 2(32) = 64 grams of O2

64 gram of O2 needs = 16 grams of CH4

1 gram of O2 needs =

$\frac{16}{64}$

10.1 gram of O =

$\frac{16}{64}\times 10.1$ of CH4

= 2.52 gram

1 mole of CO2 is produced from = 1 mole of CH4

44 gram of CO2 is produced from 16 gram of CH4

1 gram CO2 =

$\frac{16}{44}$ gram of CH4

129 gram of CO2 =

$\frac{16}{44}\times 129$ gram of CH4

= 46.90 grams

2 mole of O2 produce = 1 mole of CO2

2x 32 gram of O2 = 44 gram of CO2

1 gram of O2 =

$\frac{44}{64}$ of CO2

12.1 gram of O2 produce=

$\frac{44}{64}\times 12.1$ of CO2

= 8.318 gram

Note : Write the quantity give on left side of "="

write the substance asked on right side of "="

8 0

3 years ago

What term do you use to describe a solutio that has a lower concentration compared to another solution?

tangare [24]

If we are talking about a lower concentration of solutes then the term would be Hypotonic solution.

6 0

3 years ago

The wavelength of the violet light emitted from a hydrogen atom is 410.1 nm. This light is a result of electronic transitions be

VashaNatasha [74]

Answer:

e. 4.847 x 10-19 J

Explanation:

From the given information:

The equation connecting the photon energy and the wavelength is:

$E_{photon } = \dfrac {hc}{\lambda}$

where;

$planck's \ constant \ (h)$ = 6.626 * 10 ^{-34} J.s

$velocity \ of \ light \ (c)$ = 3.00 * 10^8 m/s

wavelength $\lambda = 410.1 \ nm \times \dfrac{10^{-9} \ m}{1 \ nm}$

$\lambda = 4.101 \times 10^{-7} \ m$

To determine the photon energy of violet light

$E_{photon } = \dfrac {(6.626 \times 10^{-34} J/s ) \times (3.00 \times 10^8 \ m/s) }{4.101 \times 10^{-7} \ m}$

= 4.847 × 10⁻¹⁹ J

4 0

3 years ago