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jok3333 [9.3K]
3 years ago
14

Between which of these pairs of elements is a covalent bond most likely to form?

Chemistry
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

The correct option here is the first option

Explanation:

Covalent bond is the bond that involves the sharing of electrons between the participating atoms. The electrons (in the outermost shells of the atoms) that are involved this sharing are called the "shared pair" while those electrons (in the outermost shells of the atoms) that are not involved in this sharing are called the "lone pair". Bonding eventually leads to each of the participating atoms achieving it's octet configuration.

Carbon will bind covalently with fluorine (to form carbon tetrafluoride) with each of the electrons on the outermost shell of the carbon been shared covalently with fluorine atoms (that also requires just one electron to achieve it's octet configuration). Thus, at the end, we would have one carbon atom being covalently linked to four flourine atoms.

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A gas has a volume of 5.00 L at 0°C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to ea
Diano4ka-milaya [45]

Answer:

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C  (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume =  87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

2)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

3)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

4 0
3 years ago
How many atoms are in c8h8o3?<br> Show your work
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Answer:

im positive that it's 19

8 0
3 years ago
An inverse relationship can be represented by:<br> a straight line<br> a bar chart
kolezko [41]

Answer:

An inverse relationship can neither be represented by a straight line nor by a bar chart. But it can be represented by "xy = k"

Explanation:

                   Inverse relation is used for the values which are inversely related to each other. For example: Let suppose you have a value x and y. Then an increase in the value of x will result in the decrease of value y. Mathematically it is represented as,

                                                         x  ∝  1 / y

Where;

              ∝ = proportionality

Replacing the proportionality sign by a constant value "k" the relation becomes,

                                                         x  =  k / y

Solving for k,

                                                         x y  =  k

Conclusion:

                  Hence, an inverse relationship can be represented by "xy = k"

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Answer:

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