We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.
The final temperature is: 75.11 °C.
The work done at constant pressure, W=nR(T₂-T₁)
n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).
W=2.4 × 10³ Joule (Given)
From the expression,
(T₂-T₁)=
(T₂-T₁)= 
(T₂-T₁)= 48.11
T₂=300+48.11=348.11 K= 75.11 °C
Final temperature is 75.11 °C.
Answer: Glucose is a simple sugar with six carbon atoms and one aldehyde group.
Explanation: hope this helps you
Arm, leg, foot, hand, head, finger, toe, nose, mouth, ears
Ne because it it just a regular element (neon)
There are 3 significant figures in the number 0.00666. They are each of the non-zero number 6's. The zero's before a number are not significant. The zeroes AFTER a number ARE significant.
For example:
0.006660 has four significant figures because there is a zero after nonzeroes.
0.00666 only has three significant figures because the zeros before a significant figure are not significant.
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