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Viefleur [7K]
3 years ago
8

The s.I unit of R so that the equation velocity= R × density S dimensionally correct R is a constant

Physics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

R = m⁴/kg . s

Explanation:

In this case, the best way to solve this is working with the units in the expression.

The units of velocity (V) are m/s

The units of density (d) are kg/m³

And R is a constant

If the expression is:

V = R * d

Replacing the units and solving for R we have

m/s = kg/m³ * R

m * m³ / s = kg * R

R = m * m³ / kg . s

<h2>R = m⁴ / kg . s</h2>

This should be the units of R

Hope this helps

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The resultant vector \vec R = \vec A+\vec B is given by \vec R = 3.196\,\hat{i}-0.464\,\hat{j}\,\,\,[m].

Explanation:

Let \vec A = 6\cdot (\cos 30^{\circ}\,\hat{i}+\sin 30^{\circ}\,\hat{j}) and \vec B = 4\cdot (-\sin 30^{\circ}\,\hat{i}-\cos 30^{\circ}\,\hat{j}), both measured in meters. The resultant vector \vec R is calculated by sum of components. That is:

\vec R = \vec A+\vec B (Eq. 1)

\vec R = 6\cdot (\cos 30^{\circ}\,\hat{i}+\sin 30^{\circ}\,\hat{j})+4\cdot (-\sin 30^{\circ}\,\hat{i}-\cos 30^{\circ}\,\hat{j})

\vec R = (6\cdot \cos 30^{\circ}-4\cdot \sin 30^{\circ})\,\hat{i}+(6\cdot \sin 30^{\circ}-4\cdot \cos 30^{\circ})\,\hat{j}

\vec R = 3.196\,\hat{i}-0.464\,\hat{j}\,\,\,[m]

The resultant vector \vec R = \vec A+\vec B is given by \vec R = 3.196\,\hat{i}-0.464\,\hat{j}\,\,\,[m].

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