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Viefleur [7K]
3 years ago
8

The s.I unit of R so that the equation velocity= R × density S dimensionally correct R is a constant

Physics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

R = m⁴/kg . s

Explanation:

In this case, the best way to solve this is working with the units in the expression.

The units of velocity (V) are m/s

The units of density (d) are kg/m³

And R is a constant

If the expression is:

V = R * d

Replacing the units and solving for R we have

m/s = kg/m³ * R

m * m³ / s = kg * R

R = m * m³ / kg . s

<h2>R = m⁴ / kg . s</h2>

This should be the units of R

Hope this helps

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If you have a 1.0 m aqueous solution of NaCl, by how much will it increase the water’s boiling point, if KB = 0.512 °C/m? In oth
fgiga [73]

<u>Answer:</u> The elevation in boiling point is 1.024°C.

<u>Explanation:</u>

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=ik_b\times m

where,

i = Van't Hoff factor = 2 (for NaCl)

\Delta T_b = change in boiling point  = ?

k_b = boiling point constant = 0.512^oC/m

m = molality = 1.0 m

Putting values in above equation, we get:

\Delta Tb=2\times 0.512^oC/m\times 1.0m\\\\\Delta Tb=1.024^oC

Hence, the elevation in boiling point is 1.024°C.

5 0
3 years ago
1. explain why mid-sized cars and SUVs have different rollover fatality rates.
iris [78.8K]

Answer:

1.  They generally have poorer fuel efficiency and require more resources to manufacture than smaller vehicles, thus contributing more to climate change and environmental degradation. Their higher center of gravity increases their risk of rollovers.

2. Mid-sized cars and SUVs both have a fixed object fatality rate of 2.6/BVM. This is most likely because they have a similar mass and inertia. The force of the crash is likely to have about the same deceleration in both vehicles.

Explanation:

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8 0
3 years ago
In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their b
lesya692 [45]

Answer:2.55 rad/s

Explanation:

Given

Diameter of ride=5 m

radius(r)=2.5 m

Static friction coefficient range=0.60-1

Here Frictional force will balance weight

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f=\mu N=\mu m\omega ^2\cdot r

weight of object=mg

Equating two

f=mg

\mu m\omega ^2\cdot r=mg

\omega ^2=\frac{g}{\mu r}

\omega =\sqrt{\frac{g}{\mu r}}

\omega =2.55 rad/sec

8 0
3 years ago
A 3600 kg rocket traveling at 2900 m/s is moving freely through space on a journey to the moon. The ground controllers find that
Nana76 [90]

Answer:

m=417.24 kg

Explanation:  

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Initial mass of rocket  M = 3600 Kg

Initial velocity of rocket vi = 2900 m/s  

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Θ = 11° angle in degrees

To find

m = mass of gas  

Solution

Let m = mass of gas    

first to find Initial speed with angle given

So

Vi=vi×tanΘ...............tan angle

Vi= 2900m/s × tan (11°)

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m = (M ×vi ×tanΘ)/( vg + vi tanΘ)

put the values as we have already solve vi ×tanΘ

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Which letter represents a wavelet
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A/c/d. that is the anser hope it helps
6 0
3 years ago
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