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DENIUS [597]
3 years ago
9

Andy took a bus and then walked from his home to downtown. For the first 1.6 hour, the bus drove at an average speed of 15 km/h

Physics
2 answers:
qwelly [4]3 years ago
6 0

Answer:

1.6x15=24

=0.4x4.5=1.8

=24+1.8=25.8

=1.6+0.4=2

=25.8/2=12.9

Yuliya22 [10]3 years ago
4 0

<em>1.6x15=24 </em>

<em> </em>

<em>0.4x4.5=1.8 </em>

<em> </em>

<em>24+1.8=25.8 </em>

<em> </em>

<em>1.6+0.4=2 </em>

<em> </em>

<em>25.8/2=12.9</em>

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A 4.33 kg cat has 41.7 J of KE How fast is the cat moving?
balandron [24]

Answer:

The answer to your question is:

Explanation:

Data

mass = 4.33 kg

E = 41.7 J

v = ?

Formula

Ke = (1/2)mv²

Clear v from the equation

v = √2ke/m

Substitution

v = √2(41.7)/4.33

v = 19.26 m/s          Result

7 0
3 years ago
If you dribble a basketball with a frequency of 1.77 Hz, how long does it take for you to complete 12 dribbles?
Licemer1 [7]
<h2>It takes 6.78 seconds to complete 12 dribbles.</h2>

Explanation:

Frequency of dribble = 1.77 Hz

That is

         Number of dribbles in 1 second = 1.77

         \texttt{Time taken for 1 dribble = }\frac{1}{1.77}=0.565s

Now we need to find how long does it take for you to complete 12 dribbles.

         Time taken for 12 dribbles = 12 x Time taken for 1 dribble

         Time taken for 12 dribbles = 12 x 0.565

         Time taken for 12 dribbles = 6.78 seconds      

It takes 6.78 seconds to complete 12 dribbles.  

8 0
3 years ago
starting from a stop a traffic signal, a car speeds up to 20 m/s in 5 seconds. calculate the acceleration of the car.
Ira Lisetskai [31]

Answer:

5.867 m/s^2

Explanation:

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8 0
3 years ago
If two waves pass a point every second what is the frequency of the waves
marishachu [46]
[two waves] pass a point [every second]... The answer is in the question (B)
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3 years ago
An 89 kg man drops from rest on a diving board −3.1 m above the surface of the water and comes to rest 0.5 s after reaching the
OLga [1]

To solve this problem we will use the linear motion kinematic equations, for which the change of speed squared with the acceleration and the change of position. The acceleration in this case will be the same given by gravity, so our values would be given as,

m= 89 kg\\x = 3.1 m\\t = 0.5s\\a = g = 9.8m/s^2

Through the aforementioned formula we will have to

v_f^2-v_i^2 = 2ax

The particulate part of the rest, so the final speed would be

v_f^2 = 2gx

v_f=\sqrt{2(9.8)(3.1)}

v_f = 7.79m/s

Now from Newton's second law we know that

F = ma

Here,

m = mass

a = acceleration, which can also be written as a function of velocity and time, then

F = m\frac{dv}{dt}

Replacing we have that,

F = (89)\frac{7.79}{0.5}

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Therefore the force that the water exert on the man is 1386.62

3 0
4 years ago
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