Question

How many grams of ethanol, C2H5OH, can be boiled with 843.2 kJ of heat energy? The molar heat of vaporization of ethanol is 38.6 kJ/mol.

Answer 1

Answer:

1.00 × 10³ g

Explanation:

Step 1: Given data

• Provided heat (Q): 843.2 kJ

• Molar heat of vaporization of ethanol (ΔH°vap): 38.6 kJ/mol

Step 2: Calculate the moles of ethanol vaporized

Vaporization is the passage of a substance from liquid to gas. We can calculate the number of moles (n) vaporized using the following expression.

Q = ΔH°vap × n

n = Q / ΔH°vap

n = 843.2 kJ / (38.6 kJ/mol) = 21.8 mol

Step 3: Calculate the mass corresponding to 21.8 moles of ethanol

The molar mass of ethanol is 46.07 g/mol.

21.8 mol × 46.07 g/mol = 1.00 × 10³ g