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Ratling [72]
4 years ago
10

Consider heat transfer between two identical hot solid bodies and their environments. The first solid is dropped in a large cont

ainer filled with water, while the second one is allowed to cool naturally in the air. For which solid is the lumped system analysis more likely to be applicable? Why?
Physics
1 answer:
sergeinik [125]4 years ago
4 0
<h2>For Second Solid Lumped System is Applicabe</h2>

Explanation:

Considering heat transfer between two identical hot solid bodies and their environments -

  • If the first solid is dropped in a large container filled with water, while the second one is allowed to cool naturally in the air than for second solid, the lumped system analysis more likely to be applicable
  • The  reason is that a lumped system analysis is more likely to be applicable in the air than in water as the convection heat transfer coefficient so that the Biot number is less than or equal to 0.1 that is much smaller in air

Biot number = the ratio of conduction resistance within the body to convection resistance at the surface of the body

∴ For a lumped system analysis Biot number should be less than 0.1

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The acceleration of The Munster’s car is 9.71 m/s2 when he applies 5050 N of net force (by way of the engine). What is the mass
Ainat [17]

Given that,

Acceleration, a = 9.71 m/s²

Force, F = 5050 N

mass, m = ?

Since, we know that

F=ma

m= F/a

m= 5050/9.71

m= 520.08 kg

The mass of hi car is 520.08 kilograms.

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3. Three blocks of masses m, 2m and 3m are suspended from the ceiling using ropes as shown in diagram. Which of the following co
Alja [10]

Answer:

The correct option is d: T₁ > T₂ > T₃.  

Explanation:

Let's evaluate each tension.

<u>Case T₃.</u>

T_{3} - W_{3} = 0

For the system to be in equilibrium, the algebraic sum of the tension force (T) and the weight (W) must be equal to zero. The minus sign of W is because it is in the opposite direction of T.          

T_{3} = W_{3}          

Since W₃ = mg, where <em>m</em> is for mass and <em>g</em> is for the acceleration due to gravity, we have:                

T_{3} = W_{3} = mg  (1)                                                                                                     <u>Case T₂.</u>

T_{2} - (T_{3} + W_{2}) = 0    

T_{2} = T_{3} + W_{2}   (2)

By entering W₂ = 2mg and equation (1) into eq (2) we have:

T_{2} = T_{3} + W_{2} = mg + 2mg = 3mg

<u>Case T₁.</u>

T_{1} - (T_{2} + W_{1}) = 0  

T_{1} = T_{2} + W_{1}    (3)

Knowing that W₁ = 3mg and T₂ = 3mg, eq (3) is:

T_{1} = 3mg + 3mg = 6mg        

Therefore, the correct option is d: T₁ > T₂ > T₃.  

I hope it helps you!

6 0
3 years ago
Read 2 more answers
What percentage of the intensity gets through both polarizers?
sp2606 [1]

Answer:

if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

Explanation:

The incident light is generally random, that is, it does not have a polarization plane, when the first polarized stops by half, this already polarized light arrives at the second polarizer and the causticity passes

                I = I₀ cos² θ

therefore if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

8 0
3 years ago
For a maximum superelevation of 0.08 ft/ft and a degree of curve of 4o, calculate the maximum safe speed for the curve assuming
Mamont248 [21]

Answer:

Explanation:

Given that

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Given curve= u•

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R = 5729.57795/D

R = 5729.57795/4

R = 1432.4ft

c + f = V^2/gG

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V^2 = 9625.728 or V = 98 ft/sec

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7 0
3 years ago
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