All categories

2 years ago

If 6 cakes cost £1.80, how much do 4 cost

1 answer:

8 0

First find the value of 1 cake by dividing the price of all six by six. £1.80/6 can be seen more simply as 180p/6 which is 30p. Therefore 1 cake is 30p. Then multiply it with 4
which is 120

You might be interested in

Find the nth term of a gp with (a. find term = 5, common ratio = 2

Rina8888 [55]

Step-by-step explanation:

we know,

$tn= a {(r)}^{n - 1} \\ T5 = a {(2)}^{5 - 1} \\ t5 = a \times {2}^{4} \\ = 16a$

Therefore, nth term of a given gp is

16a

7 0

3 years ago

What is the value of x in the following equation? -3x-2=2x+8

Arlecino [84]

Answer:

-2 =x

Step-by-step explanation:

-3x-2=2x+8

Add 3x to each side

-3x+3x-2=2x+3x+8

-2 = 5x+8

Subtract 8 from each side

-2-8 = 5x+8-8

-10 = 5x

Divide by 5

-10/5 = 5x/5

-2 =x

7 0

2 years ago

Write the first five terms of the sequence defined by the explicit formula

denis-greek [22]

<u>Answer:</u>

The correct answer option is: 19, 13, 3, -11, -29.

<u>Step-by-step explanation:</u>

We are given the following explicit formula for an arithmetic sequence:

$a_n=21-2n^2$

So to find the first five terms of this sequence, we will substitute the values of $n$ (num here in the given formula:

$a_1=21-2(1)^2\\\\a_1=19$

$a_2=21-2(2)^2\\\\a_2=13$

$a_3=21-2(3)^2\\\\a_3=3$

$a_4=21-2(4)^2\\\\a_4=-11$

$a_5=21-2(5)^2\\\\a_5=-29$

Therefore, the first five terms of the sequence defined by the explicit formula $a_n=21-2n^2$ are 19, 13, 3, -11, -29.

5 0

3 years ago

Read 2 more answers

-189=4x-3(-4x+15) help me i need help badly

lyudmila [28]

Answer:

Step-by-step explanation:

−189=4x−3(−4x+15)

−189=16x−45

16x−45=−189

16x−45+45=−189+45

16x=−144

16x /16

= −144 /16

x=−9

Good luck honey !!

7 0

3 years ago

Read 2 more answers

When i post this question i will have 690 points lol

Liula [17]

Answer:

y have 3K

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers