In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is:
log₂(2ⁿ) = n number of <span>bits
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a). <span>What is the minimum number of bits required to store each binary string of length 50?
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Answer: In this situation, we have n = 50. Therefore, 2⁵⁰ binary strings of length 50 are there and so it would require:
log₂(2⁵⁰) <span>= 50 bits.
b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
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Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:
log2(109)= 29.89
<span> = 30 bits. (rounded to the nearest whole #)
c). </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
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Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
log₂(10,4)=log₂(210) = 7.7
= 8 bits. (rounded to the nearest whole #)
Answer:
17 days and a half.
Step-by-step explanation:
First, we can find how much money he makes per day cutting lawns. This can be found with the equation:
40 x 5 = 200
He makes $200 a day cutting lawns.
Now we can divide his goal money ($3500) by his daily rate ($200) to get the number of days it will take to reach his goal.
3500 ÷ 200 = 17.5
It will take him 17.5 days to reach his goal.
We will be using the formulas:
speed=distance/time
time=distance/speed
distance=speed×time
First let's find out Diane's rate of swimming. We can measure this by finding the slope (y/x) of a given coordinate on the graph. One point is (10,15), so you do 15/10=1.5m/s
Now for Rick's rate of swimming, just take a pair of values from the table. 12.5/10=1.25m/s
By the way m/s is metres per second for this
So at a constant speed of 1.5m/s, Diane swam 150m in 150/1.5= 100 seconds, or 1 minute 40 seconds
And at a constant speed of 1.25m/s, Rick swam 150m in 150/1.25= 120 seconds, or 2 minutes.
So the difference between their two times is 20 seconds
<em>f(-4) = 13</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>f(x) = 0.5x + 15</em>
<em>replace x = - 4</em>
<em>f(-4) = 0.5×(-4) + 15</em>
<em>= - 2 + 15</em>
<em>= 15 - 2</em>
<em>= 13</em>
<em>Good luck !</em>
Answer:
5xy
Step-by-step explanation:
