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Kobotan [32]
2 years ago
15

iron has a density of 7.86 g cm3 could a block of metal with a mass of 18.2 and a volume of 2.56 cm^3 be iron?

Chemistry
1 answer:
satela [25.4K]2 years ago
7 0

The density of the block will be "7.11 gm/cm³". A further explanation is provided below.

Given values are:

Density of iron,

  • 7.86 \ g/cm^3

Mass of block of metal,

  • 18.2 \ gm

Volume of block,

  • 2.56 \ cm^3

By using the formula,

→ Density = \frac{Mass}{Volume}

then,

→ The density of block will be:

= \frac{Mass}{Volume}

= \frac{18.2}{2.56}

= 7.11 \ gm/cm^3

Learn more:

brainly.com/question/10804879

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scoundrel [369]

We can calculate for temperature by assuming the equation for ideal gas law:

P V = n R T

Where,

P = pressure = 1.80 atm

V = volume = 18.2 L

n = number of moles = 1.20 moles

R = gas constant = 0.08205746 L atm / mol K

Substituting to the given equation:

T = P V / n R

T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm / mol K)

T = 332.70 K

We can convert K unit to ˚C unit by subtracting 273.15 to Kelvin, therefore

T = 59.55 ˚<span>C</span>

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How many moles are in 48.0g of H2O2?
Tju [1.3M]

Answer:

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Explanation:

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Identify the control group the experimental group the independent variable and the dependent variable
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How many particles are in 1.40 x 10^7 mol of aluminum (Al)?
SpyIntel [72]

Answer:

<h3>Hlo there !! </h3>

<u>One mole of any substance contains 6.022*1023 structural units (atoms, molecules, ions, etc.). This number is known as the Avogadro constant.</u>

<u>One mole of any substance contains 6.022*1023 structural units (atoms, molecules, ions, etc.). This number is known as the Avogadro constant.So 1.04*107 mol of Al contains 1.40*107 * 6.022*1023 = 8.43*1030 structural units (in case of Al – atoms).</u>

<h3><u>8.43*1030 particles Al.</u></h3>

Explanation:

<h3>Hope this helps !!</h3>
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