Answer: the statement that is wrong about uncouplers is option A ( they allow ATP synthesis with no electron transport).
Explanation:
An uncoupler is a molecule that disrupts oxidative phosphorylation by dissociating the reactions of ATP synthesis from the electron transport chain. They allow electron transport without ATP synthesis. Their mechanism of action is basically to transport protons back into the matrix, preventing the required buildup of charge on the other side.
2,4-DNP is an example of an uncoupler.
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Answer:</h3>
61.3 mL
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Explanation:</h3>
From the data given;
- Mass of volumetric flask is 109.1 g
- Mass of salt is 5.01 g
- Mass of Volumetric flask and salt is 113.5 g
- Mass of volumetric flask and salt solution is 170.4 g
- Mass of salt solution is 61.3 g
We are required to calculate the volume of salt solution;
We need to know the relationship between density, mass and volume of a solution.
Density = Mass ÷ Volume
Therefore, given mass and density we can find the volume.
Rearranging the formula;
Volume = Mass ÷ density
Assuming the density of salt solution is 1 g/mL
Then;
Volume = Mass of the salt solution ÷ density of the salt solution
= 61.3 g ÷ 1 g/mL
= 61.3 mL
Therefore, the volume of the salt solution is 61.3 mL
moles NaOH = c · V = 0.2753 mmol/mL · 43.44 mL = 11.959032 mmol
moles H2SO4 = 11.959032 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 5.979516 mmol
Hence
[H2SO4]= n/V = 5.979516 mmol / 54.69 mL = 0.1093 M
The answer to this question is [H2SO4] = 0.1093 M
The equation that best represents the behavior of acetic acid in water is; CH3CO2H + H2O ⇄ CH3CO2− + H3O+.
Acetic acid, like all other acids dissociates in water. The equation for the dissociation of acetic acid in water is; CH3CO2H + H2O ⇄ CH3CO2− + H3O+.
During this dissociation, the acid proton in acetic acid is transferred to water to form the oxonium ion H3O+.
The presence of H3O+ in solution accounts for all the observed properties of acetic acid in solution.
Learn more: brainly.com/question/14072179
