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never [62]
3 years ago
10

When the air inside a school gets warmer (temperature increases), the molecules of air move faster and farther apart. True Or Fa

lse?
Chemistry
2 answers:
damaskus [11]3 years ago
6 0

Answer:

The answer is False

Explanation:

If you want a visual representation, take water. When its left at room temperature the molecules are moving but not very fast. If you bring that water to a boil, the molecules move a lot faster and get closes together. If you were to freeze that water inside a closed container you would see the water inside expand because the molecules grow further apart.

To answer the question, while the molecules do move faster, they do not move further apart.

Elodia [21]3 years ago
5 0
Answer: The answer is false
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The following exothermic reaction is allowed to reach equilibrium. What
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The answer is gonna be the last one :)
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If you put magnets together and allow them to arrange themselves, how will the poles be aligned?
vodka [1.7K]
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5 0
3 years ago
_NaHCO(s) --&gt; _CO2+_NaCO(s)+_H2O<br><br>balance the equation​
elena55 [62]

The balanced equation :

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

<h3>Further explanation</h3>

Given

Reaction

NaHCO(s) --> _CO2+_NaCO(s)+_H2O

Required

The balanced equation

Solution

Maybe the equation should be like this :

NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

Give a coefficient

NaHCO₃⇒aCO₂ + bNa₂CO₃+cH₂O

Make an equation

Na, left=1, right=2b⇒2b=1⇒b=1/2

H, left=1, right=2c⇒2c=1⇒c=1/2

C, left=1, right=a+b⇒a+b=1⇒a+1/2=1⇒a=1/2

The equation becomes :

NaHCO₃⇒1/2CO₂ +1/2Na₂CO₃+1/2H₂O x2

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

5 0
2 years ago
Which of the following are considered pure substance??
Shkiper50 [21]

Answer:

Explanation:

I’m 99.9% sure that it’s an element because it can’t be broken down any more than it already is.

7 0
3 years ago
When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at
STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

1.22 * 10^{5} = - 8.314* 2400 * ln K

\\ 1.22 * 10^{5} = -19953.6 * ln K

ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022

So, the equilibrium constant is 0.0022.

4 0
3 years ago
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