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3 years ago

Describe how electromagnetic waves are formed and travel through space.

Physics

2 answers:

schepotkina [342]3 years ago

7 0

Answer:

Electromagnetic waves are created by a charged particle that generates an electric field. The electric field creates a magnetic field. As the charged particle moves, the electric field and magnetic field keep changing, which causes the wave to move.

Explanation:

sample response 2020 edg

Maslowich3 years ago

4 0

Answer:

Explanation:

<em> I just answered the question and this is the sample response </em>

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fiasKO [112]

Answer:

Here are some of the main cons of nuclear energy.

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7 0

3 years ago

Read 2 more answers

How can motion be described and measured

PolarNik [594]

Answer:

Motion can be described "...in terms of displacement, distance, velocity, acceleration, speed, and time," according to Wikipedia. The main feature that measures motion is momentum or speed.

Hope this helped! Let me know if you have any other questions. :)

3 0

3 years ago

Read 2 more answers

An athlete at high performance inhales 4.0L of air at 1 atm and 298 K. The inhaled and exhaled air contain 0.5% and 6.2% by volu

LenaWriter [7]

To solve this problem we will calculate the total volume of inhaled and exhaled water. From the ideal gas equation we will find the total number of moles of water.

An athlete at high performance inhales 4.0L of air at 1atm and 298K.

The inhaled and exhaled air contain 0.5% and 6.2% by volume of water, respectively.

During inhalation, volume of water taken is

$V_i = (4L)(0.5\%)$

$V_i = 0.02L$

During exhalation, volume of water expelled is

$V_e = (4L)(6.2\%)$

$V_e = 0.248L$

During 40 breathes, total volume of water taken is

$V_{it} = (40L)(0.02L) = 0.8L$

During 40 breathes, total volume of water expelled out is

$V_{et} = (40L)(0.248L) = 9.92L$

Therefore resultant volume of water expelled out from the lung is

$\Delta V = 9.92L-0.8L = 9.12$

From the body through the lung we have that

$n = \frac{PV}{RT}$

Here,

P = Pressure

R= Gas ideal constant

T= Temperature

V = Volume

Replacing,

$n = \frac{(1atm)(9.12L)}{(8.314J/mol \cdot K)(298K)}$

$n = 0.373mol/min$

Therefore the moles of water per minute are expelled from the body through the lungs is 0.373mol/min

8 0

4 years ago

A mobile travels 98 km in 2h calculate: a) your speed b) how many kilometers will you travel in 3h with the same speed?

ra1l [238]

If you are traveling 98 km in 2h you are traveling 49 km/h (98/2=49).
To calculate how many kilometers you will travel in 3 hours, multiply 49 (the number of kilometers) times 3 (the number of hours) and you get 147 kilometers.

Hope that helps.

6 0

3 years ago

A relaxed biceps muscle requires a force of 25.0N for an elongation of 3.0 cm; under maximum tension, the same muscle requires a

Norma-Jean [14]

3.3 x10^4N/m²

6.7 x105N/m²

Explanation:

Let the young modulus of the relaxed biceps be

Y= F¹Lo/ deta L1 x A

= 25 x0.2/ 0.03* 50cm²(1m²

0.0004cm^-²)

= 3.3x10^4N/m²

But young modules of muscle under maximum tension will be

Y= F"Lo/ deta L" x A

= 500x 0.2/ 0.03* 50cm²(1m²

0.0004cm^-²)

= 6.7 x10^5N/m²

4 0

4 years ago