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3 years ago

When butane reacts with oxygen, the temperature of the surrounding area

2 answers:

6 0

Hello!

When butane reacts with oxygen, the temperature of the surrounding area increases.

The chemical equation for this reaction is:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

This is a combustion reaction. Combustion reactions are highly exothermic, meaning that there is a high amount of energy that is released from the breaking of the chemical bonds and the oxidation of butane to carbon dioxide. This energy is released in the form of heat, increasing the temperature of the surroundings.

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Maurinko [17]3 years ago

4 0

Answer:

increases.

Explanation:

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Reaction intermediates differ from activated complexes in that A. they are stable molecules with normal bonds and are frequently

vova2212 [387]

Answer:

they are molecules with normal bonds rather than partial bonds and can occasionally be isolated.

Explanation:

In chemistry, reaction intermediates are species that are formed from reactants and are subsequently being transformed into products as the reaction progresses. In other words, reaction intermediates are species that do not appear in a balanced reaction equation but occur somewhere along the reaction mechanism of a non-elementary reaction. They are usually short lived species that possess a high amount of energy. They may or may not be isolated.

They are often molecular species with normal bonds unlike activated complexes that are sometimes hypervalent species.

3 0

3 years ago

Someone plz help i need to do this assignment to pass the class

Natalija [7]

Answer:

1)0.2

2)0.72

3)0.01

Explanation:

Formula is 1)454÷2270

2)0.6×1.2

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8 0

2 years ago

A 1. 07 g sample of a noble gas occupies a volume of 363 ml at 35°c and 678 mmhg. Identify the noble gas in this sample. (r = 0.

Margaret [11]

The identity of the noble gas is the sample is Krypton

<h3>Ideal Gas law</h3>

From the question, we are to determine the identity of the noble gas in the sample

From the ideal gas equation, we have that

PV = nRT

∴ n = PV / RT

Where P is the pressure

V is the volume

n is the number of moles

R is the gas constant

and T is the temperature

From the given information,

P = 678 mmHg = 0.892105 atm

V = 363 mL = 0.363 L

R = 0.08206 L.atm/mol.K

T = 35 °C = 35 + 273.15 K = 308.15 K

Putting the parameters into the equation, we get

n = (0.892105 × 0.363)/ (0.08206 × 308.15)

n = 0.0128 moles

Now, we will determine the Atomic mass of the sample

Using the formula,

Atomic = Mass / Number of moles

Atomic mass of the substance = 1.07 / 0.0128

Atomic mass of the substance = 83.6 amu

The noble gas with the closest atomic mass to this value is Krypton.

Molar mass of Krypton = 83.798 amu

Hence, the identity of the noble gas is the sample is Krypton

Learn more on Ideal Gas law here: brainly.com/question/20212888

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4 0

2 years ago

2 Points

fiasKO [112]

Answer:land

Explanation:

6 0

3 years ago

For a concentration technique, Stotal is given as 19.31 ± 0.035, Smb is 0.22 ± 0.008, and kA is 0.154 ± 0.007 ppm–1, where Stota

professor190 [17]

Answer:

Explanation:

8 0

3 years ago