Answer:
I= 20 i {N.s}
Explanation:
In order to obtain the impulse on the 2 kg ball, you have to apply the equation of Impulse:
I=FΔt
Where I is the impulse vector, F is the net force and Δt is the interval of time when the force is applied.
In this case:
Δt=0.01 s
F= 2000 i N
where i is the unit vector in the x direction.
Replacing the values in the formula:
I=(2000)(0.01)i
Therefore:
I= 20 i {N.s}
Answer:
50J
Explanation:
At the top you have(A)
KE_a = O
PE_a = 100J
KE + PE = 100J
At the bottom you have (C)
KE_c= 100J
PE_c=0J
KE+PE = 100J
At point C:
You are at half the height.
We know that at H, PE =100J
PE_c = mgH
At C,
PE_c= mg (H/2) *at half the height
*m and g stay the same
Intuitively, the higher you are, the more potential energy you have.
If you decrease the height by a half, your PE will also decrease
At A:
PE_a / (mg) = H
At B:
PE_b / (mg) = H/2
to also get H on the right hand side, multiply by 2
2 (PE_b/ (mg))= H
2PE_b / (mg) = H
Ok, now that we have set up 2 equations (where H is isolated), find PE at B
AT A = AT B *This way you are saying that H = H (you compare both equations)
PE_a / (mg) = 2x PE_b / (mg)
*mg are the same for both cancel them (you can do that because of the = sign)
PE_a = 2PE_b
We know that PE_a = 100J
100J/2 = PE_b
PE at b = 50J
**FIND KE at b
We know that
KE_b + PE_b is always 100J
100J = 50J + KE_b
KE_b = 50J
Answer:
It’s 1
Explanation:
Potential difference =Work Done (in Joules)/ Total Charge(in Coulomb)
So Here
Potential difference =2J/2C
=1V
thankyou : )
The Angle between horizontal and 1.25 plane
You'd have an easier time using the equation if you understood where the equation comes from.
The law here ... the major principle to remember, the key, the fundamental truth, the big cookie ... is the fact that momentum is conserved. <em>The total momentum after they join up is the same as the total momentum before they meet.</em>
Momentum of an object is (mass) times (speed).
Now, list all the things you know, before and after the putty meets the ball:
<u>Before:</u><u> </u>There are two objects.
Mass of putty = 3 kg
Speed of putty = 5m/s
Momentum of putty = 3 x 5 = 15 kg-m/s.
Mass of ball = 5 kg
Speed of ball = zero
Momentum of ball = 5 x 0 = zero
Total momentum of both things = 15 kg-m/s
<u>After</u>: There is only one object, because they stuck together.
Mass of (putty+ball) = (3+5) = 8 kg
Speed of (putty+ball) = we don't know; that's what we have to find
Momentum of (putty+ball) = 8 x (speed)
===================================
We know that the momentum after is equal to the momentum before.
8 x (speed) = 15 kg-m/s
Divide each side by 8 :
Speed = 15 / 8 = <em>1.875 m/s </em> after they stick together.