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kompoz [17]
3 years ago
12

( TRUE false )

Physics
2 answers:
Alex73 [517]3 years ago
8 0

Answer:

number 6 is wrong

the answer is pesticides

2.combines are used for harvesting or threshing.so number <em>2</em><em> </em><em>is</em><em> </em><em>w</em><em>rong</em>

at least you tried

Explanation:

there is no such thing as <em>weedicides</em>

Sedbober [7]3 years ago
7 0

Answer:

1. True

2.True

3.False

4. True

5. True

6.False

7.False

8.True

9.False

10.False

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How know that rocks formed from the seafloor sediments deposited in the Amadeus basin were softer than the arkose sandstone
svp [43]
The rocks formed from the seafloor sediments deposited in the Amadeus basin were softer than the Arkose sandstone because the Amadeus basin were made up of marine and non-marine sedimentary rocks which are softer compared to quarts which make up mostly the Arkose sandstone.
7 0
3 years ago
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In my trigonometry class, we were assigned a problem on Angular and Linear Velocity.
Rzqust [24]

1) 0.0011 rad/s

2) 7667 m/s

Explanation:

1)

The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:

\omega=\frac{\theta}{t}

where

\theta is the angular displacement of the object

t is the time elapsed

\omega is the angular velocity

In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is

\theta=2\pi rad

And the time taken is

t=95 min \cdot 60 =5700 s

Therefore, the angular velocity of the telescope is

\omega=\frac{2\pi}{5700}=0.0011 rad/s

2)

For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation

v=\omega r

where

v is the linear velocity

\omega is the angular velocity

r is the radius of the circular orbit

In this problem:

\omega=0.0011 rad/s is the angular velocity of the Hubble telescope

The telescope is at an altitude of

h = 600 km

over the Earth's surface, which has a radius of

R = 6370 km

So the actual radius of the Hubble's orbit is

r=R+h=6370+600=6970 km = 6.97\cdot 10^6 m

Therefore, the linear velocity of the telescope is:

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4 0
3 years ago
irius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Ano
Norma-Jean [14]

The actual distance of Regulus from Earth is 23.81 parsecs.

Given:

Parallax of Regulus, p = 0.042 arc seconds

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Thus from the relation of parallax of a celestial body we get:

S = 1/ tan p ≈ 1 / p

where S is the actual distance between the object and the observer

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Here for Regulus, we get:

S = 1 / p

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We know that,

1 parsecs = 3.26 light-years = 206,000 AU

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Learn more about astronomical units here:

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6 0
1 year ago
Comparativo entre a máquina a vapor de Neu carmen e James Watt!
Bas_tet [7]

Answer:

jame watt

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James Watt tiña máis importancia que outro home

3 0
3 years ago
During Mr. Nye's science class, students were expected to identify various substances using physical properties they could easil
nydimaria [60]
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4 0
2 years ago
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