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Anon25 [30]
3 years ago
11

Which family on the periodic table is least likely to enter into chemical reactions?

Chemistry
1 answer:
Mkey [24]3 years ago
5 0

Answer:

the answer is seventeen

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How do elements heavier than iron form?
Vilka [71]

Answer:

<h2><u>neutron capture </u></h2>

<u></u>

Explanation:

<em>Hope this helps :)  </em>

<em>Pls make brainliest :3  </em>

<em>And have an amazing day <3</em>

4 0
2 years ago
PLZ HELP I WILL GIVE U BRAINLEST PLZ HELP!!!!!!!!!!
sergeinik [125]
My answer is A. I'm probably wrong. in bad in this subject
7 0
3 years ago
Read 2 more answers
Predict the decay process and write the nuclear equation of Cf- 255
matrenka [14]

Answer:

curium

−

243

,

252

/

99

Es,  

251

/

98

Cf,  

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/

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Explanation: Im not very good with this but here ya go!

8 0
2 years ago
Distinguish between sugar and non-sugar with examples.
kap26 [50]

Answer:

Reducing sugars are sugars where the anomeric carbon has an OH group attached that can reduce other compounds. Non-reducing sugars do not have an OH group attached to the anomeric carbon so they cannot reduce other compounds. ... Maltose and lactose are reducing sugars, while sucrose is a non-reducing sugar

3 0
3 years ago
What is the molality of a solution made by dissolving 137.9g of sucrose in 414.1g of water?
Daniel [21]

Answer: 2.71 moles of solute for every 1 kg of solvent.

Explanation: As you know, the molality of a solution tells you the number of moles of solute present for every 1 kg of the solvent.This means that the first thing that you need to do here is to figure out how many grams of water are present in your sample. To do that, use the density of water.500.mL⋅1.00 g1mL=500. g Next, use the molar mass of the solute to determine how many moles are present in the sample.115g⋅1 mole NanO385.0g=1.353 moles NaNO3So, you know that this solution will contain 1.353moles of sodium nitrate, the solute, for 500. g of water, the solvent.In order to find the molality of the solution, you must figure out how many moles of solute would be present for 1 kg=103g of water.103g water⋅1.353 moles NaNO3500.g water=2.706 moles NaNO3You can thus say that the molality of the solution is equal to molality=2.706 mol kg−1≈2.71 mol kg−1 The answer is rounded to three sig figs.

8 0
3 years ago
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