Consider the energy diagram below.

How many moles of Na3PO4 are in 820. grams of it?

kotegsom [21]

Answer:Hello

D is correct

Explanation:

4 0

3 years ago

You know that chemical a reacts with chemical

Jet001 [13]

The chemical reaction would most likely be written as follows:
A + B = AB
We cannot simply use the usual method of converting grams to moles since we do not have any idea on what are the identities of A and B. The only method we could use is to use the law of conservation of mass where mass inflow in a process should be equal to the mass out in the process. The total inflow of mass would be the mass of A and B and the outflow would be the product AB.

mass of A + mass of B = mass of AB
10.0 g A + 10.0 g B = mass of AB
mass of AB = 20.0 g

7 0

3 years ago

How is the number of moles of an element determined from a known mass?

goblinko [34]

the mass of 1 mole of the element is used as a conversion factor to convert grams to moles

4 0

3 years ago

The rate law for a reaction is rate=k[A][B] Which one of the following statements is false? The rate law for a reaction is Which

Andrews [41]

Answer: The reaction is first order overall.

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$Rate=k[A]^x[B]^y$

k= rate constant

For the given rate law:

$Rate=k[A]^1[B]^1$

x = 1= order with respect to A

y =1= order with respect to B

n =( x+y)= (1+1) = 2 = Total order

a) If [A] is doubled, the reaction rate will increase by a factor of 2: True

$Rate'=k[2A]^1[B]^1$

$Rate'=k[2]^1[A]^1[B]^1$

$Rate'=[2]^1\times Rate$

$Rate'=[2]\times Rate$

b) The reaction is first order overall: False

The overall order is 1+1= 2.

c) k is the reaction rate constant: True

$Rate=k[A]^x[B]^y$

k= rate constant

d) The reaction is first order in [B]: True

For the given rate law:

$Rate=k[A]^1[B]^1$

x = 1= order with respect to A

e) The reaction is first order in [A]: True

For the given rate law:

$Rate=k[A]^1[B]^1$

y =1= order with respect to B

3 0

3 years ago

4) Balance the following redox reaction in an acidic solution. What are the coefficients in front of H⁺ and Fe3+ in the balanced

Kryger [21]

Answer:

- The coefficients in front of H⁺ and Fe³⁺ are 8 and 5

- There are transferred 5 moles of e-

Explanation:

This is the reaction:

Fe²⁺(aq) + MnO₄⁻(aq) → Fe³⁺(aq) + Mn²⁺(aq)

Let's think the oxidation numbers:

Fe2+ changed to Fe3+

It has increased the oxidation number → OXIDATION

Mn in MnO₄⁻ acts with +7 and it changed to Mn²⁺

It has decreased the oxidation number → REDUCTION

Let's make the half reactions:

Fe²⁺ → Fe³⁺ + 1e⁻ (it has lost 1 mol of e⁻)

MnO₄⁻ + 5e⁻ → Mn²⁺ (it has gained 5 mol of e⁻)

Now we have to ballance the O. In acidic medium we complete with water as many oxygens we have, in the opposite side. We have 4 O in reactant side, so we fill up with 4 H2O in products side.

MnO₄⁻ + 5e⁻ → Mn²⁺ + 4H₂O

Now we have to ballance the H, so as we have 8 H in products side, we complete with 8H⁺ in reactants, this is the complete half reaction:

8H⁺ + MnO₄⁻ + 5e⁻ → Mn²⁺ + 4H₂O

Notice that have 1e⁻ in oxidation and 5e⁻ in reduction. We must multiply (x5) the half reaction of oxidation, so the electrons can be cancelled.

(Fe²⁺ → Fe³⁺ + 1e⁻ ) .5

5Fe²⁺ → 5Fe³⁺ + 5e⁻

8H⁺ + MnO₄⁻ + 5e⁻ → Mn²⁺ + 4H₂O

We sum both half reactions:

5Fe²⁺ + 8H⁺ + MnO₄⁻ + 5e⁻ → 5Fe³⁺ + 5e⁻ + Mn²⁺ + 4H₂O

The electrons are cancelled, so the ballanced reaction is this:

5Fe²⁺ + 8H⁺ + MnO₄⁻ → 5Fe³⁺ + Mn²⁺ + 4H₂O

3 0

3 years ago