1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nata [24]
2 years ago
9

A dryer is shaped like a long semi-cylindrical duct of diameter 1.5 m. The base of the dryer is occupied with water-soaked mater

ials to be dried. The base is maintained at a temperature of 370K, while the dome of the dryer is maintained at 1000 K. If both surfaces behave as blackbody, determine the drying rate per unit length experienced by the wet materials.
Engineering
1 answer:
Anestetic [448]2 years ago
6 0

Answer:

0.0371 kg/s.m

Explanation:

From the given information, let's have an imaginative view of the semi-cylinder; (The image is shown below)

Assuming the base surface of both ends of the cylinder is denoted by:

A_1  \ and   \ A_2

Thus, using the summation rule, the view factor F_{11 and F_{12 is as follows:

F_{11}+F_{12}=1

Let assume the surface (1) is flat, the F_{11} = 0

Now:

0+F_{12}=1

F_{12}=1

However, using the reciprocity rule to determine the view factor from the dome-shaped cylinder A_2 to the flat base surface A_1; we have:

A_2F_{21} = A_{1}F_{12} \\ \\ F_{21} = \dfrac{A_1}{A_2}F_{12}

Suppose, we replace DL for A_1 and

A_2 =  \dfrac{\pi D}{2}

Then:

F_{21} = \dfrac{DL}{(\dfrac{\pi D}{2}) L} \times 1 \\ \\  =\dfrac{2}{\pi} \\ \\  =0.64

Now, we need to employ the use of energy balance formula to the dryer.

i.e.

Q_{21} = Q_{evaporation}

But, before that;  let's find the radian heat exchange occurring among the dome and the flat base surface:

Q_{21}= F_{21} A_2 \sigma (T_2^4-T_1^4) \\ \\ Q_{21} = F_{21} \times \dfrac{\pi D}{2} \sigma (T_2^4 -T_1^4)

where;

\sigma = Stefan \ Boltzmann's \ constant

T_1 = base \ temperature

T_2 = temperature  \ of  \ the  \ dome

∴

Q_{21} = 0.64 \times (\dfrac{\pi}{2}\times 1.5) \times 5.67 \times 10^4 \times (1000^4 -370^4)\\ \\ Q_{21} = 83899.15 \ W/m

Recall the energy balance formula;

Q_{21} = Q_{evaporation}

where;

Q_{evaporation} = mh_{fg}

here;

h_{fg} = enthalpy of vaporization

m = the water mass flow rate

∴

83899.15 = m \times 2257 \times 10^3  \\ \\  m = \dfrac{83899.15}{ 2257 \times 10^3 }\\ \\ \mathbf{m = 0.0371 \ kg/s.m}

You might be interested in
Which statement about lean manufacturing is true when you compare it to mass production?
Len [333]
Where are the statements then bbs lol
6 0
2 years ago
Need help solving math problem using integration
notka56 [123]
Ummm did you try to add or subtract and multiply or divide that can get your answer
8 0
2 years ago
A pipeline (NPS = 14 in; schedule = 80) has a length of 200 m. Water (15℃) is flowing at 0.16 m3/s. What is the pipe head loss f
dangina [55]

Answer:

Head loss is 1.64

Explanation:

Given data:

Length (L) = 200 m

Discharge (Q) = 0.16 m3/s

According to table of nominal pipe size , for schedule 80 , NPS 14,  pipe has diameter (D)= 12.5 in or 31.8 cm 0.318 m

We know, head\ loss  = \frac{f L V^2}{( 2 g D)}

where, f = Darcy friction factor

V = flow velocity

g = acceleration due to gravity

We know, flow rate Q = A x V

solving for V

V = \frac{Q}{A}

    = \frac{0.16}{\frac{\pi}{4} (0.318)^2} = 2.015 m/s

obtained Darcy friction factor  

calculate Reynold number (Re) ,

Re = \frac{\rho V D}{\mu}

where,\rho = density of water

\mu = Dynamic viscosity of water at 15 degree  C = 0.001 Ns/m2

so reynold number is

Re = \frac{1000\times 2.015\times 0.318}{0.001}

            = 6.4 x 10^5

For Schedule 80 PVC pipes , roughness (e) is  0.0015 mm

Relative roughness (e/D) = 0.0015 / 318 = 0.00005

from Moody diagram, for Re = 640000 and e/D = 0.00005 , Darcy friction factor , f = 0.0126

Therefore head loss is

HL = \frac{0.0126 (200)(2.015)^2}{( 2 \times 9.81 \times 0.318)}

HL = 1.64 m

7 0
3 years ago
What phenomenon allows water to reach the top of a building?
Artemon [7]

Answer:

Option C: water pressure.

Explanation:

Water pressure allows water to reach the top of a building.

6 0
3 years ago
A smooth sphere with a diameter of 6 inches and a density of 493 lbm/ft^3 falls at terminal speed through sea water (S.G.=1.0027
Pachacha [2.7K]

Given:

diameter of sphere, d = 6 inches

radius of sphere, r = \frac{d}{2} = 3 inches

density,  \rho} = 493 lbm/ ft^{3}

S.G = 1.0027

g = 9.8 m/ m^{2} = 386.22 inch/ s^{2}

Solution:

Using the formula for terminal velocity,

v_{T} = \sqrt{\frac{2V\rho  g}{A \rho C_{d}}}              (1)

(Since, m = V\times \rho)

where,

V = volume of sphere

C_{d} = drag coefficient

Now,

Surface area of sphere, A = 4\pi r^{2}

Volume of sphere, V = \frac{4}{3} \pi r^{3}

Using the above formulae in eqn (1):

v_{T} = \sqrt{\frac{2\times \frac{4}{3} \pir^{3}\rho  g}{4\pi r^{2} \rho C_{d}}}

v_{T} = \sqrt{\frac{2gr}{3C_{d}}}  

v_{T} = \sqrt{\frac{2\times 386.22\times 3}{3C_{d}}}

Therefore, terminal velcity is given by:

v_{T} = \frac{27.79}{\sqrt{C_d}} inch/sec

3 0
3 years ago
Other questions:
  • What do you think are the advantages and disadvantages of isothermal constant volume high extension cycle? And how efficient do
    13·1 answer
  • At the grocery store you place a pumpkin with a mass of 12.5 lb on the produce spring scale. The spring in the scale operates su
    5·1 answer
  • The attached program (studentsGpa.cpp) uses dynamic allocation to create an array of strings. It asks the user to enter a number
    10·1 answer
  • Match the following items with their correct description.
    14·1 answer
  • Which is the correct definition of schematic? a type of computer program that project managers use to track engineers on a proje
    13·1 answer
  • Which statement describes a possible limitation on a experimental design? A. Collecting samples to analyze is expensive B. The e
    6·2 answers
  • How much metal can be removed from a cracked drum to restore surface
    9·2 answers
  • A continuous function y = ƒ(x) is known to be negative at x = 0 and positive at x = 1. Why does the equation ƒ(x) = 0 have at le
    14·1 answer
  • 8. What is the purpose of the 300 Log?
    12·1 answer
  • Air at 403 K and 1 atm enters a convergent nozzle at a velocity of 150
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!