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The angle between the earth and the sun as seen from a planet is called phase angle.
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Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7
<h3>How to solve for the value of s2 - s1</h3>
We have
= ![\frac{dv}{dt} =v't = 5-3t\\\\\int\limits^a_b {v'(t)} \, dt](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%7D%7Bdt%7D%20%3Dv%27t%20%3D%205-3t%5C%5C%5C%5C%5Cint%5Climits%5Ea_b%20%7Bv%27%28t%29%7D%20%5C%2C%20dt)
![= \int\limits^a_b {(5-3t)} \, dt](https://tex.z-dn.net/?f=%3D%20%5Cint%5Climits%5Ea_b%20%7B%285-3t%29%7D%20%5C%2C%20dt)
![5t - \frac{3t^2}{2} +c](https://tex.z-dn.net/?f=5t%20-%20%5Cfrac%7B3t%5E2%7D%7B2%7D%20%2Bc)
v2 = 5x2 - 3x2 + c
= 10-6+c
= 4+c
![s(t) = \frac{5t^2}{2} -\frac{t^3}{2} +3t + c](https://tex.z-dn.net/?f=s%28t%29%20%3D%20%5Cfrac%7B5t%5E2%7D%7B2%7D%20-%5Cfrac%7Bt%5E3%7D%7B2%7D%20%2B3t%20%2B%20c)
S2 - S1
![=(5*\frac{4}{2} -\frac{8}{2} +3*2*c)-(\frac{5}{2} *1^2-\frac{1^2}{2} +3*1*c)](https://tex.z-dn.net/?f=%3D%285%2A%5Cfrac%7B4%7D%7B2%7D%20-%5Cfrac%7B8%7D%7B2%7D%20%2B3%2A2%2Ac%29-%28%5Cfrac%7B5%7D%7B2%7D%20%2A1%5E2-%5Cfrac%7B1%5E2%7D%7B2%7D%20%2B3%2A1%2Ac%29)
= 6 + 6+c - 2+3+c
12+c-5+c = 0
7 = c
Read more on acceleration here: brainly.com/question/605631
Answer:per minute from the pumping well, a steady state was attained in about 24 hr. The draw-down at a distance of 10 ft. was 5.5 ft. and at 25 ft. was 1.21 ft.
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Answer:
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