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Gennadij [26K]
3 years ago
5

The beakers in the picture above are labeled according to the ionic solutions they contain. What metal or metals could replace c

opper in the copper(II) nitrate solution?
Chemistry
1 answer:
tangare [24]3 years ago
8 0

Explanation:

When a metal replaces another metal in solution, we say such a reaction has undergone a single displacement reaction.

In such a reaction, metal higher up in the activity series replaces another one due to their position.

To known the metal or metals that will replace the given copper, we need to reference the activity series of metals.

Every metal higher than copper in the series will displace copper from the solution.

So, there metals are: potassium, sodium, lithium, barium, strontium etc.

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ale4655 [162]

Answer:

I cant help

Explanation:

4 0
3 years ago
Which type of decay has the greatest mass?
iVinArrow [24]

The type of decay which has the greatest mass is the alpha decay. An unstable nucleus loses the most mass if the nucleus emits an alpha particle. This type of decay has the largest mass among the radioactive decay. When this particle is emitted from a nucleus, it loses two protons and two neutrons therefore large amount of mass is lost.

6 0
4 years ago
How many moles are in 22 grams of N2O?
raketka [301]

Answer:

<h3>0.4998545877562891</h3>

Explanation:

<h3>#hopeithelps</h3><h3>stay safe and keep well</h3><h3 /><h3>can you mark me as your brainliest pls</h3>
4 0
3 years ago
9. Given the following reaction:CO (g) + 2 H2(g) CH3OH (g)In an experiment, 0.45 mol of CO and 0.57 mol of H2 were placed in a 1
WITCHER [35]

Answer:

Keq=11.5

Explanation:

Hello,

In this case, for the given reaction at equilibrium:

CO (g) + 2 H_2(g) \rightleftharpoons CH_3OH (g)

We can write the law of mass action as:

Keq=\frac{[CH_3OH]}{[CO][H_2]^2}

That in terms of the change x due to the reaction extent we can write:

Keq=\frac{x}{([CO]_0-x)([H_2]_0-2x)^2}

Nevertheless, for the carbon monoxide, we can directly compute x as shown below:

[CO]_0=\frac{0.45mol}{1.00L}=0.45M\\

[H_2]_0=\frac{0.57mol}{1.00L}=0.57M\\

[CO]_{eq}=\frac{0.28mol}{1.00L}=0.28M\\

x=[CO]_0-[CO]_{eq}=0.45M-0.28M=0.17M

Finally, we can compute the equilibrium constant:

Keq=\frac{0.17M}{(0.45M-0.17M)(0.57M-2*0.17M)^2}\\\\Keq=11.5

Best regards.

3 0
4 years ago
Some fuel cells are powered by hydrogen. Scientists are looking into the decomposition of water (H2O) to make hydrogen fuel with
skad [1K]

Here we have to choose the challenge which is faced by the scientist to make a hydrogen fuel cell by using water.

The challenge that the scientists are facing a. decomposition of water requires a high energy.

For the generation of fuel cells by hydrogen the use of water (H₂O) is a challenging task as the H-O bond in  water is so strong and need high activation energy.

As per the mechanism of hydrogen fuel cell generation of H₂ is compulsory. Water remains in its solution as H₂O⇔H⁺ + OH⁻. The breaking of hydroxide ion (OH⁻) to form free hydrogen need a high energy, which cannot meet easily by any energy source.

The sun is always a renewable energy source as the energy of sun is infinitive.

The decomposition of water will only produce oxygen (O₂) and hydrogen (H₂) among which H₂ will be used in the fuel cell and O₂ is not at all harmful.

The excess O₂ is always good for the environment as it is the breathing source in the living system.

5 0
3 years ago
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