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Gennadij [26K]
3 years ago
5

The beakers in the picture above are labeled according to the ionic solutions they contain. What metal or metals could replace c

opper in the copper(II) nitrate solution?
Chemistry
1 answer:
tangare [24]3 years ago
8 0

Explanation:

When a metal replaces another metal in solution, we say such a reaction has undergone a single displacement reaction.

In such a reaction, metal higher up in the activity series replaces another one due to their position.

To known the metal or metals that will replace the given copper, we need to reference the activity series of metals.

Every metal higher than copper in the series will displace copper from the solution.

So, there metals are: potassium, sodium, lithium, barium, strontium etc.

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Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
The mass of an atom may be found by adding the
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Answer:

protons and neutrons

Explanation:

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In a combustion reaction, pentane (molar mass (MM) = 72.17 g/mol) burns, in the presence of oxygen (MM = 32.00 g/mol), to produc
ladessa [460]
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The electronegativity values of carbon, hydrogen, and nitrogen are compared in the table.
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7 0
3 years ago
Three identical flasks contain three different gases at standard temperature and pressure. Flask A contains CH4, flask B contain
erastovalidia [21]

Answer:

FLASK B WHICH CONTAINS CO2 HAS THE HIGHEST NUMBER OF MOLECULES AS IT CONTAINS THE HIGHEST MOLECULAR MASS OF 44 G/MOL.

Explanation:

Flask A contains CH4

Flask B contaims CO2

Flask C contains N2

To know the flask containing the largest number of molecules, we find the molar mass of the molecules in the flask and the largest is the one with the highest number of the relative molecular mass.

Molecular Mass of CH4 (C = 12, H =1) = ( 12 + 1*4) g/mol

= 16 g/mol

Molecular mass of CO2 (C= 12, 0= 16) = (12 + 16*2) g/mol

= 12 + 32 g/mol

= 44 g/mol

Molecular mass of N2 (N=14) = 14 * 2 g/mol

= 28 g/mol

Hence, the flask with the largest number of molecules is the flask with the highest relative molecular mass. The highest molecular mass is 44 g/mol and it is for the gas CO2 in Flask B.

So therefore, Flask B has the highest number of molecules in it.

4 0
3 years ago
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