Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.
Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.
Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.
Let the molar solubility be S upon dissociation.
PbBr₂ or Lead Bromide dissociates in pure water as follows:
PbBr₂ ----------> Pb⁺² + Br⁻
S 2S
Ksp = [Pb⁺²] [ Br⁻]
Ksp = (S) (2S)²
Ksp = 4S³
6.60 × 10⁻⁶ = 4S³
S = 0.0118M
Hence, the Molar solubility S is 0.0118M.
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What are the answer choices?
Nuclear reaction: ¹¹C → ¹¹B + e⁺(positron) + ve(electron neutrino).<span><span><span><span>
</span></span></span></span>Beta
decay is radioactive decay<span> in which
a beta ray and a neutrino are emitted from an atomic
nucleus.
There are two types of beta
decay: beta minus and beta
plus. In beta minus decay, neutron is converted to a
proton and an electron and
an electron antineutrino and in beta
plus decay, a proton is converted to a neutron and positron and an electron neutrino, so mass number does not change.</span>
The (B) answer (B) is (B) (B) (B)
According to Avogadro constant 1 mole = 6.02 x 10^23 what about 9.25 x10 ^21
that is 1 mole x ( 9.25 x10 ^21) / (6.02 x10^23) = 0.0154 moles
