What is the momentum of a golf ball with a mass of 2 kg and a velocity of 10 m/s

An emf of 28.0 mV is induced in a 501 turn coil when the current is changing at a rate of 12.0 A/s. What is the magnetic flux th

dmitriy555 [2]

Answer:

Φ = 5.589×10⁻⁵ Wb

Explanation:

The inductance of a coil is given as

L = e/(di/dt) ..................... Equation 1

Where L = inductance of the coil, e = induced e.m.f, di/dt = rate of change of current in the coil.

Also,

The inductance of each turn of the coil when a magnetic field is step up in the coil is

L = NΦ/i ................. Equation 2

Where N = number of turns, Φ = magnetic field, i = current.

equating equation 1 and equation 2

e/(di/dt) = NΦ/i

making Φ the subject of the equation,

Φ = (e×i)/N.(di/dt) .................. Equation 3

Given: e = 28.0 mV = 0.028 V, N = 501 turns, di/dt = 12.0 A/s, i = 4.00 a

Substitute into equation 3,

Φ = (0.028×4)/(12×501)

Φ = 0.112/2004

Φ = 5.589×10⁻⁵ Weber

Φ = 5.589×10⁻⁵ Wb

6 0

3 years ago

The force of Earth's gravity on a capsule in space will lessen as it moves farther away. If the capsule moves to twice its dista

Bess [88]

Answer: One quarter of the force

Explanation:

According to Newton's law of Gravitation, the force $F$ exerted between two bodies of masses $m1$ and $m2$ and separated by a distance $r$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{(m1)(m2)}{r^2}$ (1)

Where $G$ is the gravitational constant

This means that the gravity force decreases when the distance between these two bodies increases.

In this context, if the distance between the capsule and the Earth increases twice, the new distance will be $2r$ .

Substituting this distance in (1):

$F=G\frac{(m1)(m2)}{(2r)^2}$ (2)

$F=G\frac{(m1)(m2)}{4r^2}$

<u>Finally:</u>

$F=\frac{1}{4}G\frac{(m1)(m2)}{r^2}$ >>>This means the force toward Earth becomes one quarter "weaker"

3 0

3 years ago

A rectangular metal tank with an open top is to hold 171.5 cubic feet of liquid. what are the dimensions of the tank that requir

Semmy [17]

To minimize the material usage we have to have the volume requested with the minimum surface area.
The volume is:
$171.5 =xyz$
And the surface is:
$S=xy+2xz+2yz$
From the first equation we get:
$z=\frac{171.5}{xy} ; k=171.5\\ z=\frac{k}{xy}\\$
I will use k instead of a number just for the conveince.
We plug this into the second equation and we get:
$S=xy+2k\frac{1}{x}+2k\frac{1}{y}$
To find the minimum of this function we have to find the zeros of its first derivative.
Sx will denote the first derivative with respect to x and Sy will denote the first derivative with respect to Sy.
$S_x=y-2k\frac{1}{x^2}\\ S_y=x-2k\frac{1}{y^2}$
Now let both derivatives go to zero and solve the system (this will give us the so-called critical points).
$0=y-2k\frac{1}{x^2}\\
0=x-2k\frac{1}{y^2}\\
y=2k\frac{1}{x^2}\\
x=2k\frac{1}{y^2}\\$
Now we plug in the first equation into the other and we get:
$x=\frac{\frac{2k}{1}}{\frac{4k^2}{x^4}}\\
x^3=2k\\
x=(2\cdot171.5)^{1/3}\\
x=7
$
Now we can calculate y:
$y=2k\frac{1}{x^2}\\
y=2\cdot 171.5\frac{1}{7^2}=7$
And finaly we calculate z:
$z=\frac{171.5}{xy}\\
z=\frac{171.5}{7\cdot7}=3.5$
And finaly let's check our result:
$V=xyz=7\cdot7\cdot3.5=171.5$

4 0

3 years ago

Because the silt (dirt particles) in muddy water eventually settles out, the muddy water is a ______________ .

Anna35 [415]

Because the silt (dirt particles) in muddy water eventually settles out, the muddy water is a __suspension__ .

7 0

3 years ago

Read 2 more answers

How do the forces acting on a boat compare to the force acting on a plane ?

erica [24]

Answer:

on there boat there will two main forces act 1,upthrust which comes from water and air and other side on the plane air and gravity.

Explanation:

7 0

3 years ago

Read 2 more answers

What is the momentum of a golf ball with a mass of 2 kg and a velocity of 10 m/s​

What is the momentum of a golf ball with a mass of 2 kg and a velocity of 10 m/s