The distance covered by Arthur is 3t The distance covered by Betty from where Arthur started is 100 - 2t They meet each other when this distance is equal 3t = 100 - 2t t = 20 s
Since the dog has a constant speed of 5m/s, the distance that Spot has run is 5 m/s (20s) = 100 m
Hello there. <span>Arthur and Betty start walking toward each other when they are 100 m apart. Arthur has a speed of 3.0 m/s and Betty has a speed of 2.0 m/s. Their dog, Spot, starts by Arthur's side at the same time and runs back and forth between them at 5.0 m/s. By the time Arthur and Betty meet, what distance has Spot run? </span> 100 m
Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.
