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3 years ago

Hello! It would help a lot if I had assistance with this question:

Mathematics

1 answer:

lyudmila [28]3 years ago

4 0

Answer:

what grade r u in? and what unit is thar

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I need help with number 5

lara31 [8.8K]

Answer:

-14 *F

Step-by-step explanation:

-3 minus 11 is -14

hope this helps

7 0

3 years ago

Read 2 more answers

(THIS IS 6TH GRADE MATH) PLEASE HELP

garri49 [273]

Answer:

f(x)=(x sqrt(x))/(x-6)^2 is continous at x=36

Step-by-step explanation:

8 0

3 years ago

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Can you do this its a slops

Cloud [144]

Answer:

1. 1/2, rise/run and since you rise one and run 2 it'll be 1/2

2. 7/0 = undefined automatically, there is no value(undefined) if there is no run

3. rise: 28 - 18 10 5

_______ = _____ = _____ = 5

run: 4 - 2 2 1

4. 1, it rises 1 and runs 1

4 0

2 years ago

Results of a survey conducted in 15 large cities within the U.S. finds that the average commute time one way to/from work is 25.

irina1246 [14]

Answer:

We conclude that commute time in her city is less than the amount reported by the survey which is 25.4 minutes.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 25.4 minutes

Sample mean, $\bar{x}$ = 22.1 minutes

Sample size, n = 15

Alpha, α = 0.10

Sample standard deviation, s = 5.3 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 25.4\text{ minutes}\\H_A: \mu < 25.4\text{ minutes}$

We use one-tailed t(left) test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{22.1 - 25.4}{\frac{5.3}{\sqrt{15}} } = -2.411$

Now, $t_{critical} \text{ at 0.10 level of significance, 14 degree of freedom } = -1.345$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Thus, there is enough evidence to conclude that commute time in her city is less than the amount reported by the survey which is 25.4 minutes.

7 0

4 years ago

How to estimate the square root of a number that is not a perfect square? Give an example and explain how to find it step by ste

tangare [24]

Answer:

See below

Step-by-step explanation:

There is a formula for estimating square root of non-perfect square numbers
√(A²±B) = A ± B/2A
where A² is the nearest perfect square, B is the difference between the original number and the perfect square

Examples

1) √75 = √(8²+11) = 8 + 11/(2*8) = 8 + 11/16 = 8.6875
2) √114 = √(11² - 7) = 11 - 7/(2*11) = 10.6818

6 0

3 years ago