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Ksju [112]
2 years ago
11

Hello! It would help a lot if I had assistance with this question:

Mathematics
1 answer:
lyudmila [28]2 years ago
4 0

Answer:

what grade r u in? and what unit is thar

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Ending balance:$10,613.15
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8 0
2 years ago
A vase in the shape of an oblique cylinder has the dimensions shown. What is the volume of the vase?
fenix001 [56]

The image is missing so i have attached it.

Answer:

Volume = 1.5 litres

Step-by-step explanation:

Using pythagoras theorem, we can get the height (h) of the cylinder

14² + h² = 17²

h² = 289 - 196

h = √93

Now, volume of a cylinder is;

V = πr²h

In the image, r = diameter/2 = 14/2 = 7cm

Thus,

V = π × 7² × √93

V = 1485 cm³

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5 0
3 years ago
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Find the lcm of 56 and 72​
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Answer:

504

Step-by-step explanation:

4 0
3 years ago
Solve the inequality 2x – 5 &gt; 7<br> a. x&gt;6<br> b. x &gt;12<br> c. x
julsineya [31]
You start with 2x -5>7 the you add five to both sides 2x-5+5>7 +5    2x.12  then divide both sides by 2 2x divided by 2 > and 12 divided by 2 and get x>6 
3 0
3 years ago
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
3 years ago
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