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alexandr402 [8]
3 years ago
8

Both HNO3(aq) and CH3COOH(aq) can be classified as *

Chemistry
2 answers:
masya89 [10]3 years ago
7 0
Answer
Acids

Explanation
HNO3 is a strong acid (nitric acid)
lord [1]3 years ago
6 0

Answer:

acids

Explanation:

HNO3 is a strong acid (Nitric Acid)

CH3COOH is a weak acid (Acetic Acid

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Give an example of a time when you would want to increase friction.
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1) you want to increase friction when it gets cold. If you're outside and it's really cold, you're going to rub your hands to warm them up, therefore friction is increasing

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6 0
3 years ago
In a 0.20 M solution, a weak acid is 3.0% dissociated.(a) Calculate the [H₃O⁺] , pH , [OH⁻], and pOH of the solution.
marin [14]

H₃O⁺ = 6.0×10^{-3}

OH = 1.7×10^{-12}

pH = 2.22

pOH = 11.78

<h3>What is pH?</h3>

The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.

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⇒pH = -log(a_{H+})

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8 0
2 years ago
Which one of the following is different from the others A .HCl B. HF C. HBr D. HI​
lora16 [44]

Answer:

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Explanation:

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5 0
2 years ago
scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

Explanation

Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

=140 sec/ 35 s = 4 half life

Therefore 45 g after first half life = 45 x1/2 =22.5 g

               22.5 g after second half life = 22.5 x 1/2 =11.25 g

            11.25 g after third half life = 11.25 x 1/2 = 5.625 g

             5.625 after  fourth half life = 5.625 x 1/2 = 2.813

therefore 2.813 g  of Scandium 47 remains  unchanged.

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2 years ago
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