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alexandr402 [8]
3 years ago
8

Both HNO3(aq) and CH3COOH(aq) can be classified as *

Chemistry
2 answers:
masya89 [10]3 years ago
7 0
Answer
Acids

Explanation
HNO3 is a strong acid (nitric acid)
lord [1]3 years ago
6 0

Answer:

acids

Explanation:

HNO3 is a strong acid (Nitric Acid)

CH3COOH is a weak acid (Acetic Acid

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How much heat is absorbed/released when 20.00 g of NH3(g) reacts in the presence of excess O2 (g) to produce NO (g) and H2O (l)
FrozenT [24]

Answer:

a. 342.9 kJ of heat are absorbed.

Explanation:

Calculation of the moles of NH_3 as:-

Mass = 20.00 g

Molar mass of NH_3 = 17.031 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{20.00\ g}{17.031\ g/mol}

Moles= 1.1743\ mol

Given that:- \Delta H=+1168\ kJ

It means that 1 mole of NH_3 undergoes reaction and absorbs 1168\ kJ of heat

So,

1168 mole of NH_3 undergoes reaction and absorbs 1168\times 1168\ kJ of heat

<u>Amount of heat absorbed = + 342.9 KJ</u>

7 0
3 years ago
How well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure
anzhelika [568]

Answer:

A: 384

B: 0.85

C: 1.1

D: 221

Explanation:

3 0
3 years ago
Read 2 more answers
Determine the specific heat of copper from the fact that 38 g of 80°C copper are needed to raise the temperature of 15 g of wate
mars1129 [50]
From the equation q=mCΔT, set the q of copper = to q of water,

So --- mCΔT(copper)=mCΔT(water).

mass (Cu - copper) = 38g
mass (H2O - water) = 15g
C (H2O) = 4.184 J/g*C
ΔΤ (H2O) = 33-22 = 11*C
ΔΤ (Cu) = 33-80 = -47*C (the final temp is the same for both materials - thermal equilibrium)
C (Cu) = ?

So --- 38(-47)C[Cu]=15(4.184)(11)
     --- C[Cu]=690.36/(-1786) = 0.3865 J/g*C, or 0.39 in 2 sig figs. (The negative goes away, because specific heats are usually positive)
5 0
3 years ago
Which of the following has six electrons in its valence shell?
Sergeu [11.5K]
Simple...

moving along the periodic table ---->>>

Oxygen has 6.

Nitrogen has 5.

Sodium has 1.

Neon has 8.

Thus, your answer, Oxygen.
6 0
2 years ago
Read 2 more answers
The volume of an automobile air bag was 66.8 L when inflated at 25 °C with 77.8 g of nitrogen gas. What was the pressure in the
Ray Of Light [21]

Answer:

\large \boxed{\text{103 kPa}}

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 66.8 L

m = 77.8 g

T = 25 °C

Calculations:

(a) Moles of N₂

\text{Moles of N}_{2} = \text{77.8 g N}_{2} \times \dfrac{\text{1 mol N}_{2}}{\text{28.01 g N}_{2}} = \text{2.778 mol N}_{2}

(b) Convert the temperature to kelvins

T = (25 + 273.15) K = 298.15 K

(c) Calculate the pressure

\begin{array}{rcl}pV & =& nRT\\p \times \text{66.8 L} & = & \text{2.778 mol} \times \text{8.314 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 298.15 K}\\66.8p & = & \text{6886 kPa}\\p & = & \textbf{103 kPa}\end{array}\\\text{The pressure in the bag is $\large \boxed{\textbf{103 kPa}}$}

3 0
2 years ago
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