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tekilochka [14]
3 years ago
13

Using a horizontal force of 60 N, a wagon is pushed horizontally across the floor a distance of 12 meters at a constant speed of

2.3 m/s
a) What is the work done by the force?
b) What is the power supplied by the force?
Physics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

a) The work done by the force is 720 joules, b) The power supplied by the force is 138 watts.

Explanation:

a) Since force is uniform and parallel to the direction of motion, the work (W), in joules, done by the force (F), in newtons, is defined by this formula:

W = F\cdot s (1)

Where s is the travelled distance, in meters.

If we know that F = 60\,N and s = 12\,m, then the work done by the force is:

W = F\cdot s

W = (60\,N)\cdot (12\,m)

W = 720\,J

The work done by the force is 720 joules.

b) And an expression for the power supplied by the force (\dot W), in watts, is concieved by differentiating (1) in time:

\dot W = F\cdot \dot s

Where \dot s is the speed of the wagon, in meters per second.

If we know that F = 60\,N and \dot s = 2.3\,\frac{m}{s}, then the power supplied by the force is:

\dot W = F\cdot \dot s

\dot W = (60\,N)\cdot \left(2.3\,\frac{m}{s} \right)

\dot W = 138\,W

The power supplied by the force is 138 watts.

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marishachu [46]

Answer:

1.93 m/s

Explanation:

Parameters given:

Mass = 4.5g = 0.0045kg

Spring constant = 8.0 N/m

Length of barrel = 13 cm = 0.013m

Frictional force = 0.035N

Compression = 5.8 cm = 0.058m

First, we find the P. E. stored in the spring:

P. E. = ½*k*x²

P. E. = ½ * 8 * 0.058² = 0.013J

Then, we find the work done by the frictional force while the sphere is leaving the barrel of the gun:

Work = Force * distance

The distance here is the length of the barrel.

Work = 0.035 * 0.13 = 0.0046 J

The kinetic energy of the sphere can now be found:

K. E. = P. E. - Work done

K. E. = 0.013 - 0.0046 = 0.0084J

We can now find the speed using the formula for K. E.:

K. E. = ½*m*v²

0.0084 = ½ * 0.0045 * v²

v² = 0.0084/0.00255 = 3.733

=> v = 1.93 m/s

4 0
3 years ago
Read 2 more answers
A Porsche challenges a Honda to a 400 m race. Because the Porsche's acceleration of 3.4 m/s2 is larger than the Honda's 3.0 m/s2
padilas [110]

Answer:

Winner wins by 0.969 s

Explanation:

For the Porche:

Given:

Displacement of Porsche s = 400 m

Acceleration of Porsche a = 3.4 m/s^2

From Newton's second equation of motion,

s = ut + (1/2) a t^2 (u = 0 as the car was initially at rest)

Substituting the values into the equation, we have

t^2 = (2 * 400) / 3.4

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t = 15.33 s

For the Honda:

Displacement of Honda = 310 m

Acceleration of Honda = 3 m/s^2

Applying Newton's second equation of motion

s = ut + (1/2) a t^2 (u = 0 for same reason)

Substituting the values into the equation, we obtain

t^2 = (2 * 310) / 3

= 620 / 3

t = 14.37 s

Hence

The winner (honda) wins by a time interval of = 15.33 - 14.37    

=0.969 s

8 0
3 years ago
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Dafna1 [17]

Answer:

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Answer:

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