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tekilochka [14]
3 years ago
13

Using a horizontal force of 60 N, a wagon is pushed horizontally across the floor a distance of 12 meters at a constant speed of

2.3 m/s
a) What is the work done by the force?
b) What is the power supplied by the force?
Physics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

a) The work done by the force is 720 joules, b) The power supplied by the force is 138 watts.

Explanation:

a) Since force is uniform and parallel to the direction of motion, the work (W), in joules, done by the force (F), in newtons, is defined by this formula:

W = F\cdot s (1)

Where s is the travelled distance, in meters.

If we know that F = 60\,N and s = 12\,m, then the work done by the force is:

W = F\cdot s

W = (60\,N)\cdot (12\,m)

W = 720\,J

The work done by the force is 720 joules.

b) And an expression for the power supplied by the force (\dot W), in watts, is concieved by differentiating (1) in time:

\dot W = F\cdot \dot s

Where \dot s is the speed of the wagon, in meters per second.

If we know that F = 60\,N and \dot s = 2.3\,\frac{m}{s}, then the power supplied by the force is:

\dot W = F\cdot \dot s

\dot W = (60\,N)\cdot \left(2.3\,\frac{m}{s} \right)

\dot W = 138\,W

The power supplied by the force is 138 watts.

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Water enters a student's house 10.0 m above the ground through a pipe with a cross section area of 1.00 x 10-4m2 at ground. Insi
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Answer:

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Given that;

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Therefore, in 90sec:

45 L =  90 A₁V₁

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A₁V₁ = A₂V₂

0.5*10⁻⁴ * 10 = 1*10⁻⁴ V₂

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Using Bernoulli's equation;

P₁ + pgh₁ + 1/2PV₁²  (inside)      =       P₂ + pgh₂ + 1/2PV₂²   (ground level)

1.01*10⁵ + 1000*9.8*10 + 1/2*1000*(10)² = P₂ + 0 + 1/2*1000*(5)²

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cheers I hope this helped !!

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