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Vlad1618 [11]
3 years ago
8

A net force applied to a 15.0 kg box produced an acceleration of 4.2 m/s2. If the same net force was applied to a 10 kg box, wha

t would be the acceleration to the nearest tenth of a m/s2?
Physics
1 answer:
igor_vitrenko [27]3 years ago
8 0

Answer:

6.3\ m/s^2

Explanation:

Given that,

If the mass of a body is 15 kg and produced an 4.2 m/s², we need to find the acceleration if the mass is 10 kg and the same force is applied.

Force is given by :

F = ma

Since force is same

m_1a_1=m_2a_2\\\\a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{15\times 4.2}{10}\\\\a=6.3\ m/s^2

So, if the mass is 10 kg, acceleration is 6.3\ m/s^2

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Which has zero acceleration?
Llana [10]

At rest, when travelling at a constant speed, and when in mechanical equilibrium, there is no acceleration and answer choice D is correct.

<h3>How would you define acceleration?</h3>

In mechanics, acceleration describes the rate at which a driving object's velocity changes over time. They are accelerations and vector quantities. The direction of an object's acceleration is determined by the direction of the net force acting on it. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. The car is positively accelerating if the speed is increasing. As the car slows down, its speed decreases. A decline in speed is referred to as negative acceleration. In both situations, the car is traveling ahead, yet one has a positive acceleration and the other a negative one.

To learn more about acceleration, click here:

brainly.com/question/2303856

#SPJ4

3 0
2 years ago
Describe 2 ways that mass and weight are the same
navik [9.2K]
Anything that has mass has weight and anything that has weight has mass simple.
7 0
4 years ago
vA 61.2-kg circus performer is fired from a cannon that is elevated at an angle of 57.8 ° above the horizontal. The cannon uses
dsp73

Answer:

The effective spring constant of the firing mechanism is 1808N/m.

Explanation:

First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

v_0_x=\frac{x}{t}\\ \\v_0\cos\theta=\frac{x}{t}\\\\v_0=\frac{x}{t\cos\theta}

(This is correct because the horizontal motion has acceleration zero). Then:

v_0=\frac{20.8m}{(2.60s)\cos57.8\°}\\\\v_0=15.0m/s

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

E_0=E_f\\\\U_e=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\\implies k=\frac{mv^2}{x^2}

Then, plugging in the given values, we obtain:

k=\frac{(61.2kg)(15.0m/s)^2}{(2.76m)^2}\\\\k=1808N/m

Finally, the effective spring constant of the firing mechanism is 1808N/m.

3 0
3 years ago
can someone help me answer this? i dont get it and I need help before the next 30 minutes. ill give a brainiest to whoever helps
Zinaida [17]

Answer:

S=5.83...

Explanation:

s=d/t

Speed=distance/time

s=35/10

s=5.83...

3 0
4 years ago
a traffic light at an intersection is hanging from two wires of equal length making angles of 10 degrees below the horitzontal.
aleksandrvk [35]

The tensions in the wires at the given angle of inclination is determined as 434.1 N.

<h3>Tension on the wire</h3>

The tension in the wires is calculated as follows;

T = Wsinθ

where;

  • T is tension in each wire
  • W is weight of the traffic light

T = 2500 x sin(10)

T = 434.1 N

Thus, the tensions in the wires at the given angle of inclination is determined as 434.1 N.

Learn more about tension here: brainly.com/question/918617

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3 0
2 years ago
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