At rest, when travelling at a constant speed, and when in mechanical equilibrium, there is no acceleration and answer choice D is correct.
<h3>How would you define acceleration?</h3>
In mechanics, acceleration describes the rate at which a driving object's velocity changes over time. They are accelerations and vector quantities. The direction of an object's acceleration is determined by the direction of the net force acting on it. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. The car is positively accelerating if the speed is increasing. As the car slows down, its speed decreases. A decline in speed is referred to as negative acceleration. In both situations, the car is traveling ahead, yet one has a positive acceleration and the other a negative one.
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Anything that has mass has weight and anything that has weight has mass simple.
Answer:
The effective spring constant of the firing mechanism is 1808N/m.
Explanation:
First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

(This is correct because the horizontal motion has acceleration zero). Then:

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

Then, plugging in the given values, we obtain:

Finally, the effective spring constant of the firing mechanism is 1808N/m.
The tensions in the wires at the given angle of inclination is determined as 434.1 N.
<h3>
Tension on the wire</h3>
The tension in the wires is calculated as follows;
T = Wsinθ
where;
- T is tension in each wire
- W is weight of the traffic light
T = 2500 x sin(10)
T = 434.1 N
Thus, the tensions in the wires at the given angle of inclination is determined as 434.1 N.
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