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Eva8 [605]
3 years ago
15

BOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOo

Engineering
2 answers:
gulaghasi [49]3 years ago
7 0

Answer:

BOOOooooOOOOOOOOOOOOOOOOO

Explanation:

Scorpion4ik [409]3 years ago
5 0

Answer:

SUPPPPPP

Explanation:

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A spur gearset has a module of 6 mm and a velocity ratio of 4. The pinion has 16 teeth. Find the number of teeth on the driven g
levacccp [35]

Answer:

NG=64 teeth

dG=384mm

dP=96mm

C=240mm

Explanation:

step one:

given data

module m=6mm

velocity ratio VR=4

number of teeth of pinion Np=16

<u>Step two:</u>

<u>Required</u>

1. Number of teeth on the driven gear

N_G=N_P*V_R\\\\N_G=16*4\\\\N_G=64

<em>The driven gear has 64 teeth</em>

2.  The pitch diameters

The driven gear diameter

d_G=N_G*m\\\\d_G=64*6\\\\d_G=384

<em>The driven gear diameter is 384mm</em>

The pinion diameter

<em />d_P=N_P*m\\\\d_P=16*6\\\\d_P=96<em />

Pinion diameter is 96mm

3. Theoretical center-to-center distance

C=\frac{d_G+d_P}{2} \\\\C=\frac{384+96}{2} \\\\C=\frac{480}{2}\\\\C=240

The theoretical center-to-center distance is 240mm

5 0
3 years ago
About ceramics: Generally are hard and brittle. a) True b)-False
aniked [119]

Answer:

true

Explanation:

8 0
3 years ago
The primary difference between integrated/concurrent engineering development and functional/sequential development is: Integrate
gogolik [260]

Answer:

Integrated development spends more money up front to order to save money in later stages.

Explanation:

The primary difference between integrated/concurrent engineering development and functional/sequential development is: Integrated development spends more money up front to order to save money in later stages.

Cost of integrated development is higher in the initial stages where setup has be made and proper training and education of employees are required and once it is done. It will save money in later stages.

7 0
4 years ago
Yfchggfcvkuhgvjbjhbsdfhjkibgihdfgb
Molodets [167]

Answer:

dysurygfyubiugyunhuhfnbgjdsbnm

Explanation: Because ngubduykrtvytiudhurthgvniuonssdf

8 0
3 years ago
The phasor technique makes it pretty easy to combine several sinusoidal functions into a single sinusoidal expression without us
devlian [24]

Answer:

The phasor technique can't be applied directly in the following cases:

a) 45 sin(2500t – 50°) + 20 cos(1500t +20°)

b) 100 cos(500t +40°) + 50 sin(500t – 120°) – 120 cos(500t + 60°)

c)  -100 sin(10,000t +90°) + 40 sin(10, 100t – 80°) + 80 cos(10,000t)

d)  75 cos(8t+40°) + 75 sin(8t+10°) – 75 cos(8t + 160°)

Explanation:

For a) and c), it is not possible to use the phasor technique, due this technique is only possible when the sinusoidal signals to be combined are all of the same frequency.

This is due to the vector representing a signal is showed as a fixed vector in the graph( which magnitude is equal to the amplitude of the sinusoid and his angle is the phase angle with respect to cos (ωt)), which is rotating at an angular speed equal to the angular frequency of the sinusoidal signal that represents, like a radius that shows a point rotating in a circular uniform movement.

This rotating vector represents a sinusoidal signal, in the form of a cosine (as the real part of the complex function e^{j(wt+\alpha)}), so it is not possible to combine with functions expressed as a sine, even though both  have  the same frequency.

If we look at the graphs of cos (ωt) and sin (ωt) we can say that the sin lags the cos in 90º, so we can say the following:

sin (ωt) = cos (ωt-90º)

This means that in order to be able to represent a sine function  as a cosine, we need to rotate it 90º in the plane clockwise.

This is the reason why before doing this transformation, it is not possible to use the phasor technique for b) and d).

8 0
3 years ago
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