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GarryVolchara [31]
3 years ago
6

If you dilute 19.0 mL of the stock solution to a final volume of 0.310 L , what will be the concentration of the diluted solutio

n?
Chemistry
1 answer:
Dahasolnce [82]3 years ago
6 0

Answer:

M_2=0.613M_1

Explanation:

M_1 = Concentration of stock solution

M_2 = Concentration of solution

V_1 = Volume of stock solution = 19 mL

V_2 = Volume of solution = 0.31 L= 310 mL

We have the relation

M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{M_119}{310}\\\Rightarrow M_2=M_1\times\dfrac{19}{310}\\\Rightarrow M_2=0.613M_1

\boldsymbol{\therefore M_2=0.613M_1}

The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.

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If the [H+] = 0.01 M, what is the pH of the solution, and is the solution a strong acid, weak acid, strong base, or weak base?
lana66690 [7]

Answer:

2, strong acid

Explanation:

Data obtained from the question. This includes:

[H+] = 0.01 M

pH =?

pH of a solution can be obtained by using the following formula:

pH = –Log [H+]

pH = –Log 0.01

pH = 2

The pH of a solution ranging between 0 and 6 is declared to be an acid solution. The smaller the pH value, the stronger the acid.

Since the pH of the above solution is 2, it means the solution is a strong acid.

5 0
3 years ago
Which type of energy in the bungee cord prevents the bungee jumper from hitting the ground
Effectus [21]
Elastic potential energy
7 0
3 years ago
Drought is a weather condition. true or false
ANTONII [103]

Answer:

true

Explanation:

drought is a period of unusually persistent dry weather that persists long enough to cause serious problems such as crop damage and/or water supply shortages. The severity of the drought depends upon the degree of moisture deficiency, the duration, and the size of the affected area.

7 0
3 years ago
Suppose that three isotopes of element X occur in nature as follows:
morpeh [17]

Answer:

107.5 amu

Explanation:

isotopes:                                                                     fractional      Wt Avg

           isotopes: isotopic mass   %Abundance      abundance      (amu)    

              X110              110                          60                0.60            66.0

             X105              105                         30                0.30             31.5

<u>              X100              100                         10                 0.10             10.0</u>

                                                      ∑ atm mass contributions      =    107.5 amu*

*amu = atomic mass units

5 0
2 years ago
7) Andre added 25mL of water to 75mL of a 5.0M stock solution to make 10 points
valina [46]

Answer:

The concentration of the diluted solution is 3.75 M

Explanation:

Step 1: Data given

Volume of a stock solution = 75 mL = 0.075 L

The molarity of stock solution = 5.0 M

We add 25 mL, The total volume is 100 mL = 0.100 L

Step 2: Calculate the concentration of the diluted solution

C1*V1 = C2*V2

⇒with C1 = the initial concentration = 5.0 M

⇒with V1 = the initial volume = 0.075 L

⇒with C2 = the new concentration = TO BE DETERMINED

⇒with V2 = the diluted volume = 0.100 L

5.0 M * 0.075 L = C2 * 0.100L

C2 = (5.0M * 0.075 L) / 0.100 L

C2 = 3.75 M

The concentration of the diluted solution is 3.75 M

5 0
3 years ago
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