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GarryVolchara [31]

3 years ago

6

If you dilute 19.0 mL of the stock solution to a final volume of 0.310 L , what will be the concentration of the diluted solutio

n?

1 answer:

Dahasolnce [82]3 years ago

6 0

Answer:

$M_2=0.613M_1$

Explanation:

$M_1$ = Concentration of stock solution

$M_2$ = Concentration of solution

$V_1$ = Volume of stock solution = 19 mL

$V_2$ = Volume of solution = 0.31 L= 310 mL

We have the relation

$M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{M_119}{310}\\\Rightarrow M_2=M_1\times\dfrac{19}{310}\\\Rightarrow M_2=0.613M_1$

$\boldsymbol{\therefore M_2=0.613M_1}$

The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.

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NNADVOKAT [17]

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$T_{initial} = -55.0^0C$
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Solving:
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