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3 years ago

Before you disconnect the service battery from the discharged battery, it is good practice to place a load across the

Engineering

2 answers:

Lilit [14]3 years ago

6 0

Answer:

it is true i just did this test

Explanation:

alexgriva [62]3 years ago

3 0

The answer should be true

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Are the communication skills required for a team leader in a manufacturing plant different from those of a customer service exec

Svetllana [295]

Answer:

Explanation: Excellent customer service isn’t just down to your frontline staff, but a customer might be won or lost there. That’s why it’s so important every employee works together to resolve issues and create memorable moments – and empower your frontline agents to be as valuable to the customer as possible. It could be the difference between the customer coming back again, or going elsewhere.

The following tips are designed to help both customer service representatives, customer service management, and operations staff to work together to make experiences that matter. Developing customer service skills is important for the whole team to thrive – and to ensure customers keep coming back.

Customer service representative tips

Practice active listening

Learn to empathize with your customers

Use positive language

Improve your technical skills

Know your products and services

Look for common ground

Communicate clearly

Be solutions-focused

Admit mistakes

Be willing to learn

Customer service team management and operations tips

Provide first-class training

Set your standards high

Have a clear escalation pathway

Align your touchpoints

Create a culture of excellence

Be smart about automation

Use tools that boost speed and efficiency

Measure and analyze customer feedback

Use closed-loop feedback

Listen, understand and take action

5 0

2 years ago

: The interior wall of a furnace is maintained at a temperature of 900 0C. The wall is 60 cm thick, 1 m wide, 1.5 m broad of mat

Snowcat [4.5K]

Answer:

Heat is lost at the rate of 750 J/s or W

The thermal resistance is 1 K/W

Explanation:

interior temperature $T_{2}$ = 900 °C

wall thickness t = 60 cm = 0.6 m

width = 1 m

breadth = 1.5 m

thermal conductivity k = 0.4 W/m-K

outside temperature $T_{1}$ = 150 °C

heat through the wall = ?

The area of the wall A = w x b = 1 x 1.5 = 1.5 m^2

Temperature difference $dt$ = $T_{2}$ - $T_{1}$ = 900 - 150 = 750 °C

note that $dt$ is also equal to 750 K since to convert from °C to K we'll have to add 273 to both temperature, which will still cancel out when we subtract the two temperatures.

To get the heat that escapes through the wall, we use the equation

Q = Ak $\frac{dt}{t}$