Firstly need to determine the empirical formula of the hydrocarbon. Empirical formula is the simplest whole number ratio of components of the compound. Molecular formula is the actual composition of the components in the compound.
percentage of C - 82.66%
percentage of H - (100-82.66) = 17.34 %
in 100 g of compound ;
mass of C - 82.66 g
mass of H - 17.34 g
C H
mass in 100 g 82.66 g 17.34 g
molar mass 12 g/mol 1 g/mol
number of moles 6.88 mol 17.34 mol
(mass/molar mass)
divide the number of moles by least number of moles (6.88 mol)
6.88 mol/6.88 17.34/6.88
1 2.52
multiply these by 2 to get a whole number
C - 1x 2 = 2
H - 2.52 x 2 = 5.04
round off to nearest whole number
C - 2
H - 5
ratio of C to H is 2:5
empirical formula - C₂H₅
empirical formula mass = 12 g/mol x 2 + 5 * 1 g/mol = 29 g
next have to find how many empirical units are there in the molecular unit
molecular unit mass = 58.12 g
empirical unit = 29 g
then number of empirical units = 58.12 / 29 = 2
rounded off , number of empirical units = 2
(C₂H₅) * 2 units
molecular formula = C₄H₁₀
Explanation:
If there is a chemical change, the substance must be different from sodium bicarbonate.
It must have <em>different chemical and physical properties</em>.
The question is incomplete, the remaining part of the question is
Which of the above occurs for each of the following circumstances?
A 50-milliliter sample of a 2-molar Cd(NO3)2 solution is added to the left beaker.
Answer:
Voltage decreases but remains > zero.
Explanation:
Given the balanced redox reaction equation:
2Ag^+(aq) + Cd(s) ---------------> 2 Ag(s) + Cd^2+(aq)
Concentration affects the cell voltage according to Nernst equation. Change in concentration must lead to a change in cell Voltage.
As the concentration of the Cd(NO3)2 solution is increased, voltage decreases because of the increase in the concentration values but voltages remains above zero.
Answer:
The temperature would be too cold
Explanation:
I think the anwser is A but I'm not sure so I might need to get somebody else's opinion like i said I'm sorry if it's wrong
