<span>NaCl is poster-compound for ionic bonding. The bonds in NaCl have about 70% ionic character, making the bond highly polar. its overstatement to state that there is actual ion in NaCl with +1 and -1 charge but actual charge of Na and Cl is +1 and -1 ion, since Nacl exist as a network of highly charged particle and not discrete molecule, NaCl particle does not exhibit intermolecular forces.
Water molecule on other hand exhibit London dispersion force, keesom force, and hydrogen bonding.
The polar water molecule are attracted to the polarized Na and Cl atoms. This is what allow NaCl(s) to dissolve and ionize in water. Therefore type of attraction in NaCl is ion-dipole attraction.</span>
        
             
        
        
        
KAnswer:
See explanation
Explanation:
It is more common to use H2SO4 for dehydration reaction rather than HCl because HCl contains a good nucleophile,the chloride ion.
Owing to the presence of the chloride ion, a substitution reaction involving the chloride ion may also proceed also thereby affecting the elimination reaction.
Also, concentrated H2SO4 is a very good drying agent thus, as long as it is used, the alcohol substrate is completely dehydrated to yield the alkene.
Note that HCl is not a dehydrating agent.
 
        
             
        
        
        
Answer: 0.43molO₂
Explanation:
The ideal gas law for moles is  . If you did not know, R is the ideal gas constant,
. If you did not know, R is the ideal gas constant,  .
.
Since the temperature must be in Kelvin, we must convert our given temperature from ℃ to K. 
Now that we have the temperature converted to Kelvin, we can plug in our information to the ideal gas law for the number of moles.



Therefore, the number of moles is 0.43molO₂.
I hope this helps! Pls mark brainliest!! :)
 
        
             
        
        
        
Answer:
70g Na 
Explanation:
The sodium reacts with water as follows:
2Na + 2H2O → 2NaOH + H2
<em>Where 2 moles of Na produce 1 mole of H2.</em>
To solve this question we must find the moles of H2. With the balanced equation we can find the moles of Na and its mass as follows:
<em>Moles H2:</em>
PV = nRT; n = PV/RT
<em>Where P is pressure = 1atm,</em>
<em>V is volume = 34L,</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 273.15K = 0°C</em>
Replacing:
n = 1atm*34L/0.082atmL/molK*273.15K
n = 1.52 moles H2
<em>Moles Na:</em>
1.52 moles H2 * (2mol Na / 1mol H2) = 3.04 moles Na
<em>Mass Na-Molar mass: 22.99g/mol-</em>
3.04 moles Na * (22.99g / mol) = 
<h3>70g Na </h3>