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Airida [17]
3 years ago
13

The smaller the mass of an object, the _____ its inertia

Physics
2 answers:
givi [52]3 years ago
4 0

Answer:

The inertia of an object does not change. The only time the inertia would change is when the object changes mass. ... The acceleration of an object depends on the mass of the object as well as the force exerted. This means that if the mass is smaller, the acceleration will be greater.

Explanation:

kirill115 [55]3 years ago
4 0

Answer:

larger

Explanation:

just trust me

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A hockey player is wearing ice skates and pushes against the wall propelling her backward on the ice. According to Newton's thir
Amiraneli [1.4K]

I do not know of the following in your class, but the wall is still and non-moving, while the hockey player is pushing off of it, as stated. So, this is not inertia, for a fact, because the wall is not moving towards the hockey player.

5 0
3 years ago
The magnitude​ R, measured on the Richter​ scale, of an earthquake of intensity I is defined as Requalslog StartFraction Upper I
lapo4ka [179]

Answer:

R = 6.8

Explanation:

Given data:

Richter scaleR = log(\frac{I}{I_o})

where R - magnitude of earthquake of Richter scale

I - quake's intensity =  10^{6.8} \times I_o

I_o - minimum intensity earthquake

Plugging all information in the equation to get Richter's scale

R = log(\frac{10^{6.8} \times I_o}{I_o})

R = log(10^{6.8})

R = 6.8

6 0
3 years ago
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3 years ago
Read 2 more answers
Compare these two collisions of a PE student with a wall.
Stolb23 [73]

1) The variable that is different in the two cases is \Delta t, the duration of the collision

2) The change in momentum is the same in the two cases

3) The impulse is the same in the two cases

4) Case B will experience a greater force

Explanation:

1)

The variable that is different in the two cases is \Delta t, the duration of the collision.

In fact, in the first case the wall is padded: this means that the collision will be "softer" and therefore will last longer, so the duration of the collision, \Delta t, will be larger.

In the second case instead, the wall is unpadded: this means that the collision is "harder" and so it will last less time, therefore the duration of the collision \Delta t will be smaller.

2)

The change in momentum in the two cases is the same.

In fact, the change in momentum is given by:

\Delta p = m(v-u)

where:

m is the mass of the student

u is the initial velocity

v is the final velocity

In both cases, we have:

m = 75 kg

u = 8 m/s

v = 0 (they both comes to rest)

Therefore, the change in momentum is

\Delta p = (75)(0-8)=-600 kg m/s

3)

The impulse in the two cases is the same.

In fact, impulse is defined as the product of force applied, F, and duration of the collision, \Delta t:

J=F \Delta t

However, the force can be rewritten as product of mass (m) and acceleration (a), according to Newton's second law:

F=ma

So the impulse is

J=ma\Delta t

The acceleration can be rewritten as rate of change of velocity:

a=\frac{\Delta v}{\Delta t}

So the impulse becomes

J=m\frac{\Delta v}{\Delta t}\Delta t = m\Delta v

So, the impulse is equal to the change in momentum: and since in the two cases the change in momentum is the same, the impulse is the same as well.

4)

The force in the collision is related to the impulse by

J=F\Delta t

where

J is the impulse

F is the force

\Delta t is the duration of the collision

The equation can be rewritten as

F=\frac{J}{\Delta t}

In the two situations described in the problem (A and B), we already said that the impulse is the same (because the change in momentum is the same). However, in case A (padded wall) the time \Delta t is longer, while in case B (unpadded wall) the time \Delta t is shorter: since the force F is inversely proportional to the duration of the collision, this means that in case B the student will experience a greatest force compared to case A.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

3 0
4 years ago
How many neutrons are needed to initiate the fission reaction shown?
nalin [4]

Answer: One neutron

Explanation:

one neutron 1/0n

Sum up the mass numbers on the right 99 + 135 + 2 = 236.

The sum of the mass numbers on the left should equal 236. 235 + 1 = 236

4 0
4 years ago
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