Hi there!
We can begin by calculating the time taken to reach its highest point (when the vertical velocity = 0).
Remember to break the velocity into its vertical and horizontal components.
Thus:
0 = vi - at
0 = 16sin(33°) - 9.8(t)
9.8t = 16sin(33°)
t = .889 sec
Find the max height by plugging this time into the equation:
Δd = vit + 1/2at²
Δd = (16sin(33°))(.889) + 1/2(-9.8)(.889)²
Solve:
Δd = 7.747 - 3.873 = 3.8744 m
Answer:
6666.67 Newtons
Explanation:
The formula F=ma (force is equal to mass multiplied by acceleration) can be used to calculate the answer to this question.
In this case:
- mass= 0.1mg= 1*10^-7 kg
- velocity= 4.00*10^3 m/s
- time= 6.00*10^-8 s
Using velocity and time, acceleration can be calculated as:
Substituting these values into the formula F=ma, the answer is:
- F= (1*10^-7)kg * (6.667*10^10) m/s²
- F= 6666.67 Newtons of force
Answer:
So lift will be 30.19632 N
Explanation:
We have given area of the wing 
We know that density of air 
Speed at top surface 
and speed at bottom surface 
According to Bernoulli's principle force is given by
