2 years ago

A fisherman moves from one end of a boat to another

1 answer:

5 0

Answer:

That isnt a question so no one will know the answer to what you are talking about. I suggest adding a sceenshot or picture of the question.

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Martha wants to calculate an object's velocity. What will she need to do?

rjkz [21]

Answer:

you divide the distance by the time it takes to travel that same distance, then you add your direction to it.

4 0

1 year ago

HELP! What are 5 changes that a fidget spinner can be?

noname [10]

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I would hope they can change this question

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2 years ago

4-08 t 1 - / S P = 1 / P = S 1 S= P Def. of Speed

nordsb [41]

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2 years ago

A larger object is made of two balls separated by a massless rigid rod that is 1.5 m long. The mass of the red ball at one end i

lions [1.4K]

Answer:

The speed of the 1 kg red ball 8.04 m/s .

Explanation:

Given :

Separation between rods , d = 1.5 m .

Mass of the red ball is 1 kg .

Mass of the orange ball is 5.7 kg .

Angular velocity , $\omega=1\ rev/s = 2\pi\ rad/s$ .

Now , distance of center of mass from red ball is :

$r =\dfrac{0\times 1+1.5\times 5.7}{1+5.7}\\\\r = 1.28\ m$

We know , speed is given by :

$v=\omega r\\\\v=2 \times \pi \times 1.28\\\\v=8.04\ m/s$

Hence , this is the required solution .

5 0

2 years ago

A positive charge of 8.0 × 10-4 C is in an electric field that exerts a force of 3.5 × 10-4 N on it. What is the strength of the

Gennadij [26K]

Answer:

E = 0.437 N/C

Explanation:

Given that,

Charge, $q=8\times 10^{-4}\ C$

Electric force, $F=3.5\times 10^{-4}\ N$

Let the strength of the electric field is E. We know that, the electric force is given by :

F = qE

Where

E is the electric field strength

$E=\dfrac{F}{q}\\\\E=\dfrac{3.5\times 10^{-4}}{8\times 10^{-4}}\\E=0.437\ N/C$

So, the strength of the electric field is equal to 0.437 N/C.

6 0

2 years ago