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vagabundo [1.1K]
3 years ago
10

Two objects of mass 5 kg and 8 kg at rest F1 and F2 meters force applied on both the boxes respectively If the speed of both the

objects after 5 sec become 16m/s and 15m/s respectively find the value of F1 and F2?
Physics
1 answer:
elena55 [62]3 years ago
7 0

Answer:

<em><u>F1 </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em><em><u> </u></em><em><u>N </u></em><em><u>and </u></em><em><u>F2 </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>4</u></em><em><u> </u></em><em><u>N</u></em>

Explanation:

<em>Formula </em><em>used </em><em>=</em><em>></em><em> </em><em> </em><em>F </em><em>=</em><em> </em><em>m×</em><em>a</em><em> </em><em>and </em><em>v-u=</em><em> </em><em>at</em>

So, as we know force = mass × acc.

so acc. of first block = <math> F1/5 </math>. and acc. of second block = <math> F2/ 8 </math>.......... so as v-u= at.. now

Here u= 0 as the objects are placed at rest initially..

thus, v= at

<em>FOR </em><em>1</em><em>S</em><em>T</em><em> </em><em>BLOCK</em>

16= <math> F1/5 </math> × 5 ==> <em><u>F1 </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em><em><u> </u></em><em><u>N</u></em>

<em>FOR </em><em>2</em><em>N</em><em>D</em><em> </em><em>BLOCK</em>

15= <math> F2/ 8 </math> × 5 ==> <em><u>F2=</u></em><em><u> </u></em><em><u>2</u></em><em><u>4</u></em><em><u> </u></em><em><u>N</u></em>

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