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3 years ago

Question 5 of 10

Chemistry

2 answers:

vladimir1956 [14]3 years ago

7 0

Answer:

Solar eclipse

Explanation

Alex_Xolod [135]3 years ago

6 0

Answer:

Neap Tide

Explanation:

A-P-E-X

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What happens when sugar is heated? Give a balanced equation

mario62 [17]

Answer:

when the sugar is heated it turn out in caramelize

8 0

2 years ago

Lithium (Li): 1s 2sB<br> A=<br> B=

topjm [15]

Answer:

A = 2

B = 1

Explanation:

The atomic number of lithium is 3.

Its atomic mass is 7 amu.

It is present in group group 1.

It has one valance electron.

Lithium is alkali metal it form salts.

It is silvery soft metal. It has lowest density as compared to all other metals.

It react vigorously with water.

It is used in rechargeable batteries which are used in camera, mobile, laptops etc.

The electronic configuration of Li:

Li₃ = 1s² 2s¹

Thus,

A = 2

B = 1

8 0

2 years ago

Help with the 3rd question plslsls I’ll brainlist.

Brilliant_brown [7]

1 - energy 2- heat 3 -plant

4 0

2 years ago

Identify the correct coefificients to balance it<br> -C3H8+O2 to -CO2 +-H2O

Iteru [2.4K]

Answer:

${\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

Explanation:

${\rm ?\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}$ .

Among the four species in this reaction, $\rm C_3H_8$ is species with the largest number of atoms per molecule. Assume that the coefficient of this compound is $1$ .

${\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}$ .

Number of atoms on the left-hand side of the reaction:

$\rm C$ : $1 \times 3 = 3$ .
$\rm H$ : $1 \times 8 = 8$ .
$\rm O$ : not found yet.

By the conservation of atoms, the number of atoms on the right-hand side of the reaction should match those on the left-hand side. In this reaction, $\rm CO_2$ is the only product with carbon atoms, whereas $\rm H_2O$ is the only product with hydrogen atoms. These $3$ carbon atoms and $8$ hydrogen atoms would correspond to:

$3 / 1 = 3$ $\rm CO_2$ molecules, and
$8 / 2 = 4$ $\rm H_2O$ molecules.

${\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

Number of atoms on the right-hand side of the reaction:

$\rm C$ : $3 \times 1 = 3$ .
$\rm H$ : $4 \times 2 = 8$ .
$\rm O$ : $3 \times 2 + 4 \times 1 = 10$ .

The number of $\rm O$ atoms on the left-hand side should match those on the right-hand side. In this reaction, $\rm O_2$ is the only reactant with $\rm O\!$ atoms. These $10$ $\rm \! O$ atoms would correspond to:

$5$ $\rm O_2$ molecules.

${\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

5 0

2 years ago

How would you test a colorless crystalline compound to determine if it was a hydrate?

Cloud [144]

A hydrate is a substance where in it contains water and other constituent elements. To know whether if that compound was a hydrate,you should record its mass, then put it in a test tube and heat it with a Bunsen burner. If the compound is a hydrate, the water in the compound will discharge in the form of water vapor. At the next 5-10 minutes, remove it in the test tube and weigh it up again. If the mass is now fewer, that means that there was water existing that has now evaporated, and the compound was a hydrate.

6 0

3 years ago