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3 years ago

Question 5 of 10

Chemistry

2 answers:

vladimir1956 [14]3 years ago

7 0

Answer:

Solar eclipse

Explanation

Alex_Xolod [135]3 years ago

6 0

Answer:

Neap Tide

Explanation:

A-P-E-X

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According to Newton’s Third Law, if someone jumps off a skateboard, the skateboard will roll backwards because -

Andrej [43]

Answer:

for the force that sent the person forward, there is an equal force pushing back on the skateboard

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4 years ago

What volume of oxygen in liters at STP wpuld be required for the combustion of 17.0 grams PH3?

Lynna [10]

First, we need to state the chemical equation for the combustion of PH3

$4PH3\text{ + 8O2 }\to\text{ P4O10 }+6H2O$

And the mass of PH3 is 17.0 grams and we need to know the moles.

In the periodic table, the atomic mass of the P (phosphorus) is 31 and the atomic mass of the H (hydrogen) is 1.

So, you sum the mass of P to the mass of H multiplied by 3 and you obtain this:

$\text{mole}cu\text{lar weight of PH3=31}\cdot1+1\cdot3=34\text{ g PH3/mol}$

With this data, we can search the moles of PH3:

7 0

1 year ago

Thermal energy only depends on the temperature of an object. true or false ?

Aleks [24]

This answer to the question is True

7 0

3 years ago

Be sure to answer all parts. Solving the Rydberg equation for energy change gives ΔE = R[infinity]hc [ 1 n12 − 1 n22 ] where the

icang [17]

Answer:

Explanation:

Utilizing Rydber's equation:

ΔE = Z²Rh ( 1/n₁² - 1/n₂²) and substituting the values given ( using the Rydbers constant value in Joules ), we have

n=1 to n= infinity

ΔE = 3² x (1/1² - 0) x 2.18 x 10⁻^18 J = 2.0 x 10⁻¹⁷ J (1/infinity is zero)

n= 3 to n= infinity

ΔE = 3² x (1/3² - 0) x 2.18 x 10⁻^18 J = 2.28 x 10^-18 J

b. The wavelength of the emitted can be obtained again by using Rydberg's equation but this time use the constant value 1.097 x 10⁷ m⁻¹ given in the problem .

1/λ = Z²Rh (1/n₁² - 1/n₂²) 10 ⁻¹ = 3² x 1.097 x 10⁷ m⁻¹ x (1/1² - 1/3²) m⁻¹

1/λ =8.8 x 10⁷ m⁻¹ ⇒ λ =1.1 x 10^-8 m

λ = 1.1 x 10^-8 m x 1 x 10⁹ nm/m = 11 nm

7 0

3 years ago

Read 2 more answers

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = $R=\frac{8.24 mL}{t}$

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = $R'=\frac{3.86 mL}{t}$

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{R}{R'}=\sqrt{\frac{M}{32 g/mol}}$

$\frac{\frac{8.24 mL}{t}}{\frac{3.86 mL}{t}}=\sqrt{\frac{M}{32 g/mol}}$

$M=\frac{32 g/mol\times 8.24 \times 8.24}{3.86\times 3.86}=145.82 g/mol$

4 0

3 years ago