A unit of ppm has an acronym of parts per million. The
equivalent units of ppm is therefore mg/L and mg/kg. So the ppm is:
mass Ca+ = 1.3 g = 1300 mg
ppm = 1300 mg / 3100 kg
<span>ppm = 0.42 ppm</span>
Answer:
Displacement Reaction
Explanation:
Zinc replaces lead in Lead(ll) nitrate as zinc is more reactive than lead.
Answer:
<h2>pH = 3.9</h2><h2>pOH = 10.1</h2>
Explanation:
Since
is a weak acid to find the pH of
we use the formula
![pH = - \frac{1}{2} log(Ka) - \frac{1}{2} log(c)](https://tex.z-dn.net/?f=pH%20%3D%20%20-%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%20log%28Ka%29%20%20-%20%20%5Cfrac%7B1%7D%7B2%7D%20%20log%28c%29%20)
where
Ka is the acid dissociation constant
c is the concentration
From the question
Ka of
= 1.75 × 10^-5
c = 1.00 × 10-³M
Substitute the values into the above formula and solve for the pH
That's
![pH = \frac{1}{2} ( - log(1.75 \times {10 }^{ - 5} - log(1.00 \times {10}^{ - 3} ) ) \\ = \frac{1}{2} (4.757 + 3) \\ = \frac{1}{2} \times 7.757) \\ = 3.8785 \: \: \: \: \: \: \: \:](https://tex.z-dn.net/?f=pH%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%28%20-%20%20log%281.75%20%5Ctimes%20%7B10%20%7D%5E%7B%20-%205%7D%20-%20%20log%281.00%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%203%7D%20%29%20%20%29%20%20%5C%5C%20%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%284.757%20%20%2B%203%29%20%5C%5C%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%207.757%29%20%5C%5C%20%20%3D%203.8785%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20)
We have the answer as
<h3>pH = 3.9</h3>
To find the pOH we use the formula
pH + pOH = 14
pOH = 14 - pH
pOH = 14 - 3.9
We have the answer as
<h3>pOH = 10.1</h3>
Hope this helps you
Answer:
region 2 and region 3
Explanation:
you can tell by the color of the land my friends^^
Here is the answer for the three of them
<span>N20 = 16 e-
</span><span>SeCl2 =20
</span><span>PBr3 = 26
Remember that t</span><span>o find the valence electrons in an atom you need to identify what group the element is in. An element in group 1A has 1 valence electron. If the element is in group 2A, then it has two valence electrons.</span>