The heat released by the water when it cools down by a temperature difference AT
is Q = mC,AT
where
m=432 g is the mass of the water
C, = 4.18J/gºC
is the specific heat capacity of water
AT = 71°C -18°C = 530
is the decrease of temperature of the water
Plugging the numbers into the equation, we find
Q = (4329)(4.18J/9°C)(53°C) = 9.57. 104J
and this is the amount of heat released by the water.
11.2
Step-by-step-explanation
Answer:
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Answer:
373.88 torr
Explanation:
P1 = 350 torr
T1 = 20°C = (20 + 273.15)K = 293.15K
P2 = ?
T2 = 40°C = (40 + 273.15)K = 313.15K
From pressure law,
Pressure of a given mass of gas is directly proportional to its temperature.
P = KT
K = P / T
P1 / T1 = P2 / T2
Solve for P2
P2 = (P1 * T2) / T1
P2 = (350 * 313.15) / 293.15
P2 = 109602.5 / 293.15
P2 = 373.878 torr
P2 = 373.88 torr
The new pressure of the gas would be 373.88 torr.
