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Lesechka [4]
3 years ago
11

How many grams of lead would be required to make 119 grams of water

Chemistry
2 answers:
Ludmilka [50]3 years ago
8 0

Answer:

(119 g H2O) / (18.01532 g H2O/mol) x (1 mol Pb / 2 mol H2O) x (207.21 g Pb/mol) = 684 g Pb

Explanation:

Strike441 [17]3 years ago
6 0

Answer:

684

Explanation:

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