Answer:
3.68 m/s².
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 9.4 ms¯¹
Maximum height (h) reached = 12 m
Final velocity (v) = 0 (at maximum height)
Acceleration of free fall (g) =?
v² = u² – 2gh (since the rock is going against gravity)
0 = 9.4² – 2 × g × 12
0 = 88.36 – 24g
Collect like terms
0 – 88.36 = –24g
–88.36 = –24g
Divide both side by –24
g = –88.36 / –24
g = 3.68 m/s²
Thus, the acceleration of free fall near the surface of Mar is 3.68 m/s².
It would do exactly what a rock or a frisbee does when you toss it.
After the engines cut off, it couldn't get any more energy from
anywhere, and after that, as it pushed air aside to get through,
and had air molecules scraping against it, those would slowly
rob kinetic energy from it. Sooner or later it would run out of
kinetic energy, start falling, and it would eventually make either
a big 'SPLOOSH' or else a big 'CRUNCH', depending on exactly
where it returned to Earth's surface.
Answer:
Explanation:
High concentrations of hydrogen ions yield a low pH (acidic substances), whereas low levels of hydrogen ions result in a high pH (basic substances). The overall concentration of hydrogen ions is inversely related to its pH and can be measured on the pH scale