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2 years ago

I REALLY NEED HELP WITH PHYSICS ASAP!!!Vf^2 = v0^2 + 2a (xf - x0)Solve for a

Physics

1 answer:

ELEN [110]2 years ago

7 0

Answer:

a. solve for a

$vf ^{2} = vo ^{2} + 2a(xf - xo) \\ 2a(xf - xo) = vf^{2} - vo ^{2} \\ a = \frac{vf^{2} - vo^{2} }{2(xf - xo)} \\ a = \frac{vf ^{2} - vo ^{2} }{2xf - 2xo}$

I hope I helped you ^_^

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Explanation:

In order to solve this problem, we need to start by drawing a diagram of the given situation. (See attached image).

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Which simplifies to:

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So we get:

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Now we can substitute the provided values into our equation. So we get:

$\frac{dh}{dt}= \frac{(8m^{3}/s)(25)}{16 \pi (4m)^{2}}$

so:

$\frac{dh}{dt}=0.25m/s$

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