Answer: For the elementary reaction
the molecularity of the reaction is 2, and the rate law is rate = ![k[NO_3]^1[CO]^1](https://tex.z-dn.net/?f=k%5BNO_3%5D%5E1%5BCO%5D%5E1)
Explanation:
Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.
Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.
Molecularity of the reaction is defined as the number of atoms, ions or molecules that must colloid with one another simultaneously so as to result into a chemical reaction. Thus it can never be fractional.
For elementary reaction
, molecularity is 2 and rate law is ![rate=k[NO_3]^1[CO]^1](https://tex.z-dn.net/?f=rate%3Dk%5BNO_3%5D%5E1%5BCO%5D%5E1)
Answer:
7200 kPa
Explanation:
Applying,
PV/T = P'V'/T'................ Equation 1
Where P = Initial pressure of neon gas, V = Initial volume of neon gas, T = Initial temperature of neon gas, P' = Final pressure of neon gas, V' = Final volume of neon gas, T' = Final Temperature of neon gas
Make P' the subject of the equation
P' = PVT'/V'T.............. Equation 2
Given: P = 900 kPa, V = 8.0 L, T = 300 K, V' = 2.0 L, T' = 600 K
Substitute these values into equation 2
P' = (900×8×600)/(2×300)
P' = 7200 kPa
V²+ = (B)
X³+ = (D)
Y³- = (C)
Z²- = (A)
When an element loses electrons, the element gains a positive charge
When an element gains electrons, the element gains a negative charge
NOTE: Electrons are negative charges
Hey, its alright bro! I gotchu.
Im pretty sure the galactic symbol is the same reference to the symbol of the element on the periodic table.
For an example (Hydrogen) is H
So if im correct im pretty sure its referring to the symbols for each element
Hopefully this helps
I’m pretty sure true, just not your skull at birth hehe. hope this helps :)