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ch4aika [34]
3 years ago
3

Which statement best describes John Dalton's use of creativity in his work? He reinterpreted and retested Joseph Proust's result

s. He used a philosophy to conduct his experiment. He recorded his results as four parts of the atomic theory. He rejected Democritus's idea that matter was composed of atoms.
Chemistry
2 answers:
Scilla [17]3 years ago
5 0

Answer: The correct statement is that,

'He reinterpreted and retested Joseph Proust's results'

Explanation:

John Dalton was an English chemist who contributed greatly to the field of Chemistry. He published his theory about atom in 1808.

Dalton was the first person to recognize a workable distinction between the fundamental particle of an element (atom) and that of a compound (molecule). The atomic theory generally summaries the laws of chemical composition which includes:

--> law of constant composition and

---> law of multiple proportions.

John Dalton was being creative in his work by reinterpretation and retesting of Joseph Proust's results. Joseph Proust was a French chemist that first discovered the law of constant composition in 1794. This means that many has started working on the atoms before John Dalton discovery.

From the previous works of Proust, he had studied tin oxides and found that their masses were either 88.1% tin and 11.9% oxygen or 78.7% tin and 21.3% oxygen (these were tin(II) oxide and tin dioxide respectively). Dalton retested and noted from these percentages that 100g of tin will combine either with 13.5g or 27g of oxygen; 13.5 and 27 form a ratio of

Dalton reinterpreted it by finding an atomic theory of matter that could elegantly explain this common pattern in chemistry – in the case of Proust’s tin oxides, one tin atom will combine with either one or two oxygen atoms. I hope this helps, thanks.

Nady [450]3 years ago
4 0

Answer:

A.) He reinterpreted and retested Joseph Proust's results

Explanation:

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EastWind [94]

Answer: D) 2.37°C

Explanation:

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3 0
2 years ago
Diethyl ether is produced from ethanol according to the following equation:
juin [17]
The balanced chemical equation is given as:

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

We are given the yield of  CH3CH2OCH2CH3 and the amount of ethanol to be used for the reaction. These values will be the starting point for the calculations.

Theoretical amount of product produced:
329 g CH3CH2OH ( 1 mol / 46.07 g ) ( 1 mol CH3CH2OCH2CH3 / 2 mol CH3CH2OH ) (74.12 g / mol ) = 264.66 g CH3CH2OCH2CH3 

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6 0
3 years ago
Briefly discuss interpretations of your observations and results. Discuss how your observations illustrated LeChatelier's princi
Dvinal [7]

Answer:

Le Chatelier's principle can be applied in explaining the results

Explanation:

According to Le Chatelier's principle, when a constraint such as a change in concentration in this case is imposed on a chemical system in equilibrium, the system will adjust itself in such a way as to annul the constraint imposed.

Hence, when the color of the solution was more like that of the control, the reaction would shift towards the left. Similarly, when the color was more like it was towards the reactant, the reaction would shift towards the right.

If we were to prepare calcium oxalate, we should prepare it in a base solution. This is because when the base was added to calcium oxalate, it did not form any precipitate but when an acid was added to the calcium oxalate, it formed a precipitate.

4 0
3 years ago
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zhuklara [117]

Explanation:

1.

Cu(NO3)2 + 2NaCl(aq) --> CuCl2(aq) + 2NaNO3(aq)

2.

Cu(NO3)2 + 2NaOH(aq) --> Cu(OH)2(s) + 2NaNO3(aq)

A light blue precipitate of Cu(OH)2 is formed and NaNO3 in solution.

3.

Cu(NO3)2(aq) --> Cu2+(aq) + 2NO3^-2(aq)

2NaOH(aq) --> 2Na+(aq) + 2OH-(aq)

Cu2+(aq) + 2OH-(aq) --> Cu(OH)2(aq)

2Na+(aq) + 2NO3^-2(aq) --> 2NaNO3(aq)

4.

The reaction in both Questions 1 and 2 is called Double displacement reaction. A double-replacement reaction exchanges the cations and/or or the anions of two ionic compounds. A precipitation reaction is a double-replacement reaction in which one product is a solid precipitate (precipitated) while the other in solution.

Since the cation and anions in Qustion 1 were exchanged, the same was done for Question 2, hence the identity of the precipitate in Question 2 was got.

6 0
3 years ago
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spayn [35]

Answer:

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5 0
3 years ago
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