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Over [174]
3 years ago
6

Statement I: At the same temperature lighter gas molecules have a higher average velocity than heavier gas molecules.

Physics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

Statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1

Explanation:

Both the velocity and kinetic energy of a gas molecule depends on its relative molecular mass according to Graham's law of diffusion in gases. Hence, the greater the relative molecular mass of the gas, the lesser its average velocity and kinetic energy.

Hence we can see that statement 2 vividly explains the postulation of statement 1 and makes the points more easily comprehensible.

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Ted throws an object straight up into the air with an initial velocity of 54 ft/s from a platform that is 40 ft above the ground
elena-s [515]

Answer:

The time it will take for the object to hit the ground will be 4.

Explanation:

You have:

h(t)=−16t²+v0*t+h0

Being v0 the initial velocity (54 ft/s) and  h0 the initial height (40 ft) and replacing you get:

h(t)=−16t²+54*t+40

To know how long it will take for the object to touch the ground, the height h(t) must be zero. So:

0=−16t²+54*t+40

Being a quadratic function or parabola: f (x) = a*x² + b*x + c, the roots or zeros of the quadratic function are those values ​​of x for which the expression is 0. Graphically, the roots correspond to the points where the parabola intersects the x axis. To calculate the roots the expression is used:

\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}

In this case you have that:

  • a=-16
  • b= 54
  • c= 40

Replacing in the expression of the calculation of roots you get:

\frac{-54+\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}  Expresion (A)

and

\frac{-54-\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)} Expresion (B)

Solving the Expresion (A):

\frac{-54+\sqrt{5476 } }{2*(-16)}= \frac{-54+74}{2*(-16)}=\frac{20}{2*(-16)}=\frac{20}{-32}= -\frac{5}{8}

Solving the Expresion (B):

\frac{-54-\sqrt{5476 } }{2*(-16)}= \frac{-54-74}{2*(-16)}=\frac{-128}{2*(-16)}=\frac{-128}{-32}= 4

These results indicate the time it will take for the object to hit the ground can be -5/8 and 4. Since the time cannot be negative, then <u><em>the time it will take for the object to hit the ground will be 4.</em></u>

6 0
3 years ago
If an electrostatically charged object is placed near other objects what will occur
bazaltina [42]
<span>If an electrostatically charged object is placed near other objects, </span>it would be attracted to objects with an opposite charge.
4 0
3 years ago
A 112 kg man stands 551 m from a building of 25,500 kg. What is the gravitational force of the man due to the
dimulka [17.4K]

C.

Explanation:

because they are equal in direction and differ in magnitude

7 0
3 years ago
What will happen to the period of a ball-on-a-spring if the ball is replaced by a smaller one with half the mass
Murrr4er [49]

When the ball on a spring is replaced by a smaller ball with half the mass :  The period decrease by 29%

<h3>Calculate the Period </h3>

We will apply the formula below to calculate period

T = 2\pi \sqrt{\frac{m}{k } }

 where :

T₁ / T₂ = \sqrt{\frac{m_{1} }{m_{2} } }    where m₂ = m₁ / 2

Therefore :

T₂ = \frac{T_{1} }{\sqrt{2} }   = 0.71 T

Hence we can conclude that the period will decrease by 29% ( i.e 100 - 71 ).

Learn more about Period calculation : brainly.com/question/10728818

4 0
2 years ago
Why does a charged balloon stick to a neutral wall?
Jobisdone [24]
<span>When you bring a charged object, such as your balloon, near a neutral object that is classified as an insulator, than a temporary charge is induced in the neutral object. If the charged object is positive, then electrons in the neutral object will be attracted toward the charged object, creating a temporary imbalance of charges in the neutral object.</span>



7 0
3 years ago
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