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Dahasolnce [82]
3 years ago
5

What are the differences between elastic and inelastic collisions when it comes to how momentum is conserved and spread between

the balls after a collision?
Physics
1 answer:
Kazeer [188]3 years ago
4 0

Answer:

Collision can be classified as either elastic or inelastic. The main difference between elastic and inelastic collisions is that, in elastic collisions, the total kinetic energy of the colliding objects before the collision is equal to the their total kinetic energy after the collision. In inelastic collisions, the total kinetic energy of the objects after the collision is less than the total kinetic energy of the objects before the collision.

GIVE. BRAINLIEST

PLEASE

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"miles per gallon" is the same as "miles / gallon"

The truck went 1,200 miles
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1,200 ÷ 55 = 21.81
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What is the maximum number of electrons an oxygen atom can hold in its outer energy level?
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Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen
Marta_Voda [28]

Answer:

a) that laser 1 has the first interference closer to the central maximum

c) Δy = 0.64 m

Explanation:

The interference phenomenon is described by the expression

         d sin θ = m λ

Where d is the separation of the slits, λ the wavelength and m an integer that indicates the order of interference

For the separation of the lines we use trigonometry

        tan θ = sin θ / cos θ = y / x

In interference experiments the angle is very small

          tan θ = sin θ = y / x

         d y / x = m λ

a) and b) We apply the equation to the first laser

          λ = d / 20

          d y / x = m d / 20

          y = m x / 20

          y = 1 4.80 / 20

          y = 0.24 m

The second laser

        λ = d / 15

          d y / x = m d / 15

          y = m x / 15

          y = 0.32 m

We can see that laser 1 has the first interference closer to the central maximum

c) laser 1

They ask us for the second maximum m = 2

            y₂ = 2 4.8 / 20

            y₂ = 0.48 m

For laser 2 they ask us for the third minimum m = 3

In this case to have a minimum we must add half wavelength

         y₃ = (m + ½) x / 15

         m = 3

         y₃ = (3 + ½) 4.8 / 15

         y₃ = 1.12 m

        Δy = 1.12 - 0.48

        Δy = 0.64 m

4 0
3 years ago
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