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Naily [24]
3 years ago
11

A 5 kg block accelerates across a horizontal surface at 7 m/s^2 when you exert a 60 N force on it. What is the force of friction

on the block (Ffs/b)?
If you don’t mind finding the kinetic friction coefficient too?
Physics
1 answer:
alina1380 [7]3 years ago
3 0
5 kg block and 7 m/s^2 = 14
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Natasha_Volkova [10]

Answer:

The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.

Explanation:

Given that,

Mass of aircraft = 10000 kg

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\Delta P.E=mg(h_{2}-h_{1})

\Delta P.E=10000\times9.8\times(10000-0)

\Delta P.E=10000\times9.8\times10000

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We calculate the change in kinetic energy

\Delta K.E=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)

\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2-0^2)

\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2)

\Delta K.E=148298642\ J

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A toroidal solenoid has an inner radius of 12.0 cm and an outer radius of 15.0 cm . It carries a current of 1.50 A . Part A How
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Answer:

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