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3 years ago

Which of the following is a compound machine

Physics

2 answers:

Ivahew [28]3 years ago

8 0

The answer is c.

Hope this helps!!!!!!!!!!

Stells [14]3 years ago

3 0

The answer is bicycle

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Why is dose equvialent in rem or sv used to define the Effective Dose Equivalent and the Committed Dose Equivalent?

Komok [63]

Good question next question

8 0

4 years ago

Mr. and Mrs. miller both have blue eyes. Could any of their children be born with brown eyes? Circle yes or no. What tule or rea

Aloiza [94]

Answer:

yes

Explanation:

Generally, darker colors dominate so a person with one brown-eyed gene and one blue-eyed gene will have brown eyes. The only way to present blue eyes is to inherit two copies of the blue-eyed gene. However, brown-eyed parents can pass a recessive blue-eyed gene. Therefore, two brown-eyed partners can birth a blue-eyed baby.

6 0

3 years ago

A blue-green photon (λ = 488 nm ) is absorbed by a free hydrogen atom, initially at rest. What is the recoil speed of the hydrog

Natalka [10]

Answer:

The recoil speed is $2.207\times 10^{4} m/s$

Solution:

Wavelength of a blue-green photon, $\lambda_{BG} = 488 nm = 488\times 10^{- 9} m$

Now, the energy associated with the blue-green photon:

$E_{BG} = \frac{hc}{\lambda_{BG}}$

where

h = Planck's constant

C = speed of light ion vacuum

$E_{BG} = \frac{6.626\times 10^{- 34}\times 3\times 10^{8}}{488\times 10^{- 9}}$

$E_{BG} = 4.07\times 10^{- 19} J$

Also, we know that the recoil speed can be calculated by the KInetic energy which is equal to the Energy of the blue-green photon:

$KE_{H} =\frac{1}{2}m_{p}v_{H}$

where

$v_{H}$ = velocity of Hydrogen atom

$m_{p} = 1.67\times 10^{- 27} kg$ = mass of H-atom

Now,

$KE_{H} =\frac{1}{2}m_{p}(v_{H})^{2}$

$4.07\times 10^{- 19} =\frac{1}{2}\times 1.67\times 10^{- 27}\times (v_{H})^{2}$

$v_{H} = \sqrt(4.87\times 10^{8}) = 2.207\times 10^{4} m/s$

7 0

3 years ago

One of the most studied objects in the night sky is the Crab nebula, the remains of a supernova explosion observed by the Chines

erica [24]

Answer:

The angular speed of the Crab nebula pulsar is 190.3 rad/s.

Explanation:

Given that,

Time T= 33 ms = 0.033 s

The angular speed is equal to the 2π divided by time period.

We need to calculate the angular speed of the Crab nebula pulsar

Using formula of angular speed

$\omega=\dfrac{2\pi}{T}$

Where, T = time

$\omega$ = angular speed

Put the value into the formula

$\omega=\dfrac{2\pi}{0.033}$

$\omega=190.3\ rad/s$

Hence, The angular speed of the Crab nebula pulsar is 190.3 rad/s.

7 0

3 years ago

Looters break a statue into pieces. how do you expect the weathering of pieces of rock to change

Naya [18.7K]

This definitely has to do with erosion. We can expect that the statue will weather faster because of more surface area.I hope this is what you were looking for

7 0

4 years ago