First convert the speed of mosquito to m/s:
So the mosquito is flying at (2,400/3,600) m/s,
or ⅔ m/s.
<span>
Since you are moving at 2m/s, so this makes the closing
velocity between you and the mosquito to be 2⅔ m/s. </span>
Therefore the mosquito will hit your sunglasses at:<span>
35 m / (2⅔ m/s) = 13⅛ seconds.
2.0 m/s * 13⅛ s = 26¼ m from your initial position.
<span>⅔ m/s * 13⅛ s = 8¾ m from the mosquito's initial position. </span></span>
Answer:
This means that the Lewis dot structure for C2H6 must account for 14 valence electrons, either through bonding between atoms, or through lone pairs. So, the two C atoms are placed in the center of the molecule.
Answer:
X: period
Y: tangential speed
Explanation:
100% on quiz your welcome(:
Answer:
The focal length of the appropriate corrective lens is 35.71 cm.
The power of the appropriate corrective lens is 0.028 D.
Explanation:
The expression for the lens formula is as follows;

Here, f is the focal length, u is the object distance and v is the image distance.
It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.
Put v= -71.4 cm and u= 24.0 cm in the above expression.


f= 35.71 cm
Therefore, the focal length of the corrective lens is 35.71 cm.
The expression for the power of the lens is as follows;

Here, p is the power of the lens.
Put f= 35.71 cm.

p=0.028 D
Therefore, the power of the corrective lens is 0.028 D.
Answer:
The inducerd emf is 1.08 V
Solution:
As per the question:
Altitude of the satellite, H = 400 km
Length of the antenna, l = 1.76 m
Magnetic field, B = 
Now,
When a conducting rod moves in a uniform magnetic field linearly with velocity, v, then the potential difference due to its motion is given by:

Here, velocity v is perpendicular to the rod
Thus
e = lvB (1)
For the orbital velocity of the satellite at an altitude, H:

where
G = Gravitational constant
= mass of earth
= radius of earth

Using this value value in eqn (1):
