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Rus_ich [418]
2 years ago
11

What would be Kelley's weight be in newtons if her mass was 70 kilograms

Physics
2 answers:
ad-work [718]2 years ago
8 0

Answer:

Kelly's weight would be 688.47 Newtons.

Explanation:

1 Kilogram would be 9.81 Newtons.

xxMikexx [17]2 years ago
5 0

It all depends on where Kelley is at the moment.

-- If she's on Mars, she weighs 229 N.

-- If she's on the Moon, she weighs 113N.

-- If she's on Earth, she weighs 686 N.

-- If she's in a space capsule coasting from one body to another, then there's no instrument that can measure any weight of her.

So it completely depends on where she happens to be at the moment.

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As the shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly at -4.1 m/s^2 as it slows from 9.0 m/
zhuklara [117]

Acceleration  =  (change in speed) / (time for the change)

      - 4.1 m/s²  =  (-9 m/s)  /  (time for the change)

Time for the change  =  (-9 m/s) / (-4.1 m/s²)  =   2.2 seconds
3 0
3 years ago
How many coulombs of charge do 50 * 10^31 electrons possess
Angelina_Jolie [31]
Quantity of Charge , Q = ne
Where n = number of electrons
             e = charge on one electron = -1.6 * 10 ^-19  C.
             n = 50 * 10^31  electrons

Q =    (50 * 10^31)*( -1.6 * 10 ^-19 ) =  -8 * 10^13 C.

Note that the minus sign indicates that the charge is a negative charge.
7 0
3 years ago
If an object starts from rest, what is its initial velocity?
Vladimir79 [104]

Answer:

0 m/s

Explanation:

velocity= change in displacement/ time

at rest, the ball does not travel any distance

0/ t

=0

4 0
3 years ago
A rock falls off a cliff. How fast will it be going after falling for 4.33 seconds?
bixtya [17]

Answer:42.43m/s

Explanation:According to vf=vi+at, we  can calculate it since v0 equals to 0. vf=0+9.8m/s^2*4.33s= 42.434m/s

4 0
1 year ago
A girl stands on the edge of a merry-go-round of radius 1.71 m. If the merry go round uniformly accerlerates from rest to 20 rpm
Mashutka [201]

Answer:

a = 0.53 m/s^2

Explanation:

initially the merry go round is at rest

after 6.73 s the merry go round will accelerates to 20 rpm

so final angular speed is given as

\omega = 2\pi f

\omega = 2\pi ( \frac{20}{60})

\omega = 2.10 rad/s

so final tangential speed is given as

v = r\omega

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now average acceleration of the girl is given as

a = \frac{v_f - v_i}{\Delta t}

a = \frac{3.58 - 0}{6.73}

a = 0.53 m/s^2

8 0
3 years ago
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