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Zina [86]
3 years ago
8

Explain how you would determine how much air there is between a vector addition in the displacement of the actual trip taken. Wh

y aren’t vectors true straight-line paths in the real world? Would you expect a vector addition to be larger or smaller than the actual trip taken? Why?
Physics
1 answer:
Setler [38]3 years ago
7 0

Answer:

This is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. This enables more atoms in the metal to become aligned hence becoming more magnetized.

or...

A method of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses.

Hope this helps☺️

You might be interested in
What is the maximum velocity (in m/s) of electrons ejected from a material by 85 nm photons, if they are bound to the material b
diamong [38]

The maximum velocity of electrons is  v = 3.20 × 10¹⁵ m/s

The wavelength of photons λ = 85 nm

W = 4.66 ev

<h3>What is photoelectric effect and how velocity of photoelectrons is calculated?</h3>

     The emission of electrons happened and absorbed through the electromagnetic radiation is said to be photoelectric effect.

Photoelectric cells, photodiodes works on the principle of photoelectric effect.

According to of photoelectric effect,

                          E = hν

        Here,  hc / λ = W + KE max

                    hc / λ =  W + 1/2 mv² max

               

                   v² =  sqrt of (( hc / λ - W) (2/m))

                   I cap denotes λ ,

substituting all the values,

 v = sqrt of ( (6.623 × 10⁻³⁴ Js ) ( 3 × 10⁸ m/s) / (85 nm) - 4.66ev) (2/  9.1× 10⁻³¹

   v = sqrt of ((1.987800 ×  10⁻²⁵ / 85 × 10 ⁹ ) - 4.66 ev ) ( 2.197 × 10³⁰)          

   v = sqrt of ((2.338588 × 10⁻³⁶) - 4.66 ev ) ( 2.197 × 10³⁰)3.2

   v = 3.20 × 10¹⁵ m/s

Thus, the maximum velocity is calculated as  v = 3.20 × 10¹⁵ m/s.

Learn more about photoelectric effect,

brainly.com/question/1895423

#SPJ4

4 0
2 years ago
Help!!
Anna [14]

Compute the work done on the table:

<em>W</em> = <em>Fd</em> = (320 N) (32 m) = 10,240 J

Divide this by the given time duration to get the power output:

<em>P</em> = <em>W</em>/∆<em>t</em> = (10,240 J) / (150 s) ≈ 63.3 W

3 0
3 years ago
As a result of friction, the angular speed of a wheel changes with time according to dθ/dt = ω0e^−σt where ω0 and σ are constant
NNADVOKAT [17]

Hi there!

a.

We can use the initial conditions to solve for w₀.

It is given that:

\frac{d\theta}{dt} = w_0e^{-\sigma t}

We are given that at t = 0, ω =  3.7 rad/sec. We can plug this into the equation:

\omega(0)= \omega_0e^{-\sigma (0)}\\\\3.7 = \omega_0 (1)\\\\\omega_0 = \boxed{3.7 rad/sec}

Now, we can solve for sigma using the other given condition:

2 = 3.7e^{-\sigma (8.6)}\\\\.541 = e^{-\sigma (8.6)}\\\\ln(.541) = -\sigma (8.6)\\\\\sigma = \frac{ln(.541)}{-8.6} = \boxed{0.0714s^{-1}}

b.

The angular acceleration is the DERIVATIVE of the angular velocity function, so:

\alpha(t) = \frac{d\omega}{dt} = -\sigma\omega_0e^{-\sigma t}\\\\\alpha(t) = -(0.0714)(3.7)e^{-(0.0714) (3)}\\\\\alpha(t) = \boxed{-0.213 rad\sec^2}

c.

The angular displacement is the INTEGRAL of the angular velocity function.

\theta (t) = \int\limits^{t_2}_{t_1} {\omega(t)} \, dt\\\\\theta(t) = \int\limits^{2.5}_{0} {\omega_0e^{-\sigma t}dt\\\\

\theta(t) = -\frac{\omega_0}{\sigma}e^{-\sigma t}\left \| {{t_2=2.5} \atop {t_1=0}} \right.

\theta = -\frac{3.7}{0.0714}e^{-0.0714 t}\left \| {{t_2=2.5} \atop {t_1=0}} \right. \\\\\theta= -\frac{3.7}{0.0714}e^{-0.0714 (2.5)} + \frac{3.7}{0.0714}e^{-0.0714 (0)}

\theta = 8.471 rad

Convert this to rev:

8.471 rad * \frac{1 rev}{2\pi rad} = \boxed{1.348 rev}

d.

We can begin by solving for the time necessary for the angular speed to reach 0 rad/sec.

0 = 3.7e^{-0.0714t}\\\\t = \infty

Evaluate the improper integral:

\theta = \int\limits^{\infty}_{0} {\omega_0e^{-\sigma t}dt\\\\

\lim_{a \to \infty} \theta = -\frac{\omega_0}{\sigma}e^{-\sigma t}\left \| {{t_2=a} \atop {t_1=0}} \right.

\lim_{a \to \infty} \theta = -\frac{3.7}{0.0714}e^{-0.0714a} + \frac{3.7}{0.0714}e^{-0.0714(0)}\\\\ \lim_{a \to \infty} \theta = \frac{3.7}{0.0714}(1) = 51.82 rad

Convert to rev:

51.82 rad * \frac{1rev}{2\pi rad} = \boxed{8.25 rev}

8 0
3 years ago
A box experiencing a gravitational force of 600 N. is being pulled to the right with a force of 250 N. 825 N. frictional force a
lidiya [134]

Answer:A

Explanation:

Explanation:

Given that,

Gravitational force = 600 N

Frictional force = 25 N

Pulled by the Force = 250 N

We know that,

The gravitational force in downward and normal force act in upward. the frictional force in left side and the box pulled by the force to the right side.

The balance equation is along y-axis

The box will not move in y-axis therefore, the net force in the y-axis will be zero.

Hence, The net force in the y-direction will be zero.

8 0
3 years ago
Savannah drove 716 miles on Monday. She drove another 572 miles on Tuesday. About how many miles did she drive
Korolek [52]

Explanation:

We have,

Savannah drove 716 miles on Monday and She drove another 572 miles on Tuesday.

It is required to find the total distance covered by her altogether. It is equal to the sum of distance covered on Monday and distance covered on Tuesday. So,

d = 716 miles + 572 miles

d = 1288 miles

So, she drive 1288 miles altogether.

5 0
4 years ago
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