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icang [17]
3 years ago
14

Which of the following combustion reactions is balanced correctly? A. C4H6 + 5.5O2 4CO2 + 3H2O B. C4H6 + 4O2 4CO2 + 3H2O C. C4H6

+ 11O2 4CO2 + 3H2O D. C4H6 + 1.5O2 4CO2 + 3H2O
Chemistry
1 answer:
Airida [17]3 years ago
5 0
You must verify that the number of atoms of each type is equal on both sides of the chemical equation: same number of C, same number of H and same number of O on both sides.

<span>A. C4H6 + 5.5O2 ---> 4CO2 + 3H2O

element      reactant side      product side

C                4                        4
H                6                        3*2 = 6
O                5.5 * 2 = 11        4*2 + 3 = 11

Then, this equation is balanced.

</span>Do the same with the other equations if you want to verify that they are not balanced.

Answer: option A.
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Dalton hypothesesized that atoms are indivisible and that all atoms of an element are identical. it is now known that
Katena32 [7]

i don't understand but atoms are made of electrons an protons and neutrons..

6 0
3 years ago
It takes 281.7 kJ of energy to remove 1 mole of electrons from the atoms on the surface of lithium metal. If lithium metal is ir
Alex17521 [72]

Answer:

The maximum kinetic energy of electron is = 2.93 × 10^{-19} Joule

Explanation:

We know that total energy

E = \frac{hc}{\lambda}  ------------ (1)

Here h = plank's constant = 6.62 × 10^{-34} J s

c = speed of light = 3 × 10^{8} \frac{m}{s}

\lambda = 261 nm = 261  × 10^{-9} m

Put all these values in equation (1) we get

E = 7.6   × 10^{-19} J

We know that

Total energy = Energy to remove an electron + K.E of electron

Energy to remove an electron = \frac{281.7 (1000)}{(6.023)10^{23} }

Energy to remove an electron = 4.67  × 10^{-19} J

K.E of electron = Total energy - Energy to remove an electron

K.E of electron = 7.6   × 10^{-19} -  4.67  × 10^{-19}

K.E of electron = 2.93 × 10^{-19} Joule

Therefore the maximum kinetic energy of electron is = 2.93 × 10^{-19} Joule

3 0
3 years ago
11C. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solut
Llana [10]

For the reactants,

  • The oxidation number of hydrogen = +1
  • The oxidation number of oxygen = -2
  • The oxidation number of arsenic = +5
  • The oxidation number of carbon = +3

For the products,

  • The oxidation number of hydrogen = +1
  • The oxidation number of oxygen = -2
  • The oxidation number of arsenic = +3
  • The oxidation number of carbon = +4

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: \text{H}_{3}\text{AsO}_{4}

formula of the reducing agent: \text{H}_{2}\text{C}_{2}\text{O}_{4}

6 0
2 years ago
Fill in the blanks with appropriate options given in below:
jarptica [38.1K]

Answer:

1) -COOH

2) -NH2

3) hydrogen bonds

4) dispersion forces

5) -CH3

6) hydrogen bonds

7) negative

8) negative

9) positive

Explanation:

Alanine has a <u>-COOH</u> and a <u>-NH2</u> group available to form <u>hydrogen bonds</u> with water molecules.

Although there are some potential <u>dispersion forces</u> between the terminal <u>-CH3</u> group of alanine and hexane molecules, we expect the <u>hydrogen bonds</u> between alanine and water to be stronger.

Stronger intermolecular attractive forces between alanine and water lead to a more <u>negative ΔHmix</u> and more <u>negative (smaller positive)</u> ΔHsoln for water than for hexane.

4 0
3 years ago
What two ways can light behave as?
Evgen [1.6K]
As a wave and also as a particle. This was proposed by Einstain and it is a theory.
8 0
3 years ago
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