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babymother [125]
3 years ago
12

Please explain the difference between the theory of continental drift and the theory of plate tectonics. Please make it 3-5 sent

ences. thanks! :D
Chemistry
2 answers:
lawyer [7]3 years ago
6 0

The difference between continental drift and plate tectonics is that the theory of continental drift states that the world was made up of a single continent. The theory of plate-tectonics, on the other hand, states that earth's surface is broken into numbers of shifting plates or slabs
Lorico [155]3 years ago
3 0

Answer:

They both come from the main idea, but the theory of continental drift states that the world was made up of a single large continent. The theory of plate tectonics state that the Earth's surface was broken into smaller pieces.

Explanation:

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i think that the answer is D

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What is a supercontinent? <br><br> please help me!
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Answer:

earth land assembling together to form single large landmass

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You are running a lemonade stand with your friend. You prepared 10 liters of 0.7 molarity lemonade, but your friend did online r
olga nikolaevna [1]

Answer:

add 7.5L of water

Explanation:

M1×V1=M2×V2

M is molarity, V is volume

0.7 × 10 = 0.4 × V2

V2= 17.5L

vol. of water to add= 17.5 - 10 = 7.5L

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A rock is found to have a mass of 200 g and a volume of 100 ml. what is the rock's density?
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Mass over volume
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3 years ago
You are provided with a stock solution with a concentration of 1.0x10-5 M. You will be using this to make two standard solutions
artcher [175]

Answer:

1. V₁ = 2.0 mL

2. V₁ = 2.5 mL

Explanation:

<em>You are provided with a stock solution with a concentration of 1.0 × 10⁻⁵ M. You will be using this to make two standard solutions via serial dilution.</em>

To calculate the volume required (V₁) in each dilution we will use the dilution rule.

C₁ . V₁ = C₂ . V₂

where,

C are the concentrations

V are the volumes

1 refers to the initial state

2 refers to the final state

<em>1. Perform calculations to determine the volume of the 1.0 × 10⁻⁵ M stock solution needed to prepare 10.0 mL of a 2.0 × 10⁻⁶ M solution.</em>

C₁ . V₁ = C₂ . V₂

(1.0 × 10⁻⁵ M) . V₁ = (2.0 × 10⁻⁶ M) . 10.0 mL

V₁ = 2.0 mL

<em>2. Perform calculations to determine the volume of the 2.0 × 10⁻⁶ M solution needed to prepare 10.0 mL of a 5.0 × 10⁻⁷ M solution.</em>

C₁ . V₁ = C₂ . V₂

(2.0 × 10⁻⁶ M) . V₁ = (5.0 × 10⁻⁷ M) . 10.0 mL

V₁ = 2.5 mL

8 0
3 years ago
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